Question

我必须将Byte数组发送到我的java应用程序来自Android设备。我在android中使用ksoap2，我在java中使用axis2创建了web服务，以接收该字节数组并在服务器上创建文件以进行进一步处理。 / p>

让我给你完整的解释。我在android设备中记录一个wave文件，然后该wave文件需要在server.i上的java应用程序中发送。我已经在java应用程序中创建了一个web2服务，其中axis2名称为“ get_wave_byte“将传入的字节数组再次转换为wave文件，并将其存储在server.and android设备中我将wave文件作为字节数组发送，并将get_wave_byte（）参数中的存储路径发送。

因此我在android中创建了wave文件，之后我创建了一个将该wave文件转换为byte array的方法。在字节数组中转换wave文件的方法如下...

public static byte[] getBytesFromFile(File file) throws IOException {
        InputStream is = new FileInputStream(file);

        // Get the size of the file
        long length = file.length();

        // You cannot create an array using a long type.
        // It needs to be an int type.
        // Before converting to an int type, check
        // to ensure that file is not larger than Integer.MAX_VALUE.
        if (length > Integer.MAX_VALUE) {
            // File is too large
        }

        // Create the byte array to hold the data
        byte[] bytes = new byte[(int)length];

        // Read in the bytes
        int offset = 0;
        int numRead = 0;
        while (offset < bytes.length
               && (numRead=is.read(bytes, offset, bytes.length-offset)) >= 0) {
            offset += numRead;
        }

        // Ensure all the bytes have been read in
        if (offset < bytes.length) {
            throw new IOException("Could not completely read file "+file.getName());
        }

        // Close the input stream and return bytes
        is.close();
        return bytes;
    }

所以基本上我现在用以下代码将这些字节数组发送到java应用程序......

 File source_for_byte=new File(outFilename);//Here is my wave file

//创建临时字节数组以在字节数组中存储这些文件

 byte[] temp = new byte[(int) source_for_byte.length()];

//然后按照上面的说法调用我的方法，将文件转换为字节数组

temp=getBytesFromFile(source_for_byte);

从这里我使用ksoap2来调用java应用程序方法，其中那些数组字节作为参数，并且字符串作为文件路径以使用get_wav_byte（）方法存储在服务器上

 String NAMESPACE = "http://test.com";
                String SOAP_ACTION = NAMESPACE + METHOD_NAME;
                // NAMESPACE + method name
                final String URL = "http://192.168.3.106:8080/axis2/services/speechmain?wsdl";

                    METHOD_NAME = "get_wav_byte";
                    try {
                        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
                        request.addProperty("wavbite",temp);

                        request.addProperty("path", "D:\\sound\\latest_recognizer.wav");
                        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                                SoapEnvelope.VER11);
                        envelope.dotNet = true;
                        envelope.setOutputSoapObject(request);
                        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
                        androidHttpTransport.call(SOAP_ACTION, envelope);
                        Object result = envelope.getResponse();
                        ((TextView) findViewById(R.id.gettext1)).setText("NUMBER IS :->   "
                                 + result.toString());

                    } catch (Exception E) {
                        E.printStackTrace();
                        ((TextView) findViewById(R.id.gettext1)).setText("ERROR:"
                                + E.getClass().getName() + ":" + E.getMessage());
                    }

我的java Application方法是我从android调用如下...

 public int get_wav_byte(byte[] wavbite,String path){

        try
            {
                File dstFile = new File(path);
                FileOutputStream out = new FileOutputStream(dstFile);
                    out.write(wavbite, 0, wavbite.length);
                out.close();               
            }
            catch (IOException e)
            {
              System.out.println("IOException : " + e);
            }

         return 0;
         }

我的问题是当我运行我的Android应用程序来调用此Web服务时，它给了我以下错误

 java.lang.runtimeexception:cannot serialize:[B@40781280]

有一件事我想告诉我，我使用以下代码从我的.net应用程序调用相同的Java方法。

static void Main(string[] args)
        {
            byte[] byteArrayFile = File.ReadAllBytes("D:/Projects/ConsoleApplication1/ConsoleApplication1/1347452692320.wav");

            String mypath="D:\\sound\\bhavik_latest_copy_recorded.wav";


            short[] shortwave=ConvertBytesToShorts(byteArrayFile);
          Speech_service.speechmainPortTypeClient obj = new Speech_service.speechmainPortTypeClient();

            obj.get_wav_byte(byteArrayFile,mypath);
}

简单就像冠军一样工作并轻松存储我的波形文件

那么我的android代码中的问题是它给出了错误。

你可以告诉我哪里出错了？

提前谢谢你。

Answer 1

好的。我用

解决了我的错误

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                    SoapEnvelope.VER11);

            new MarshalBase64().register(envelope); // serialization

Answer 2

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);

    new MarshalBase64().register(envelope);   // this is will over Cannot serialize: [B@f034108 

    envelope.dotNet = true;
    //Set output SOAP object
    envelope.setOutputSoapObject(request);
    //Create HTTP call object
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

    try {
        androidHttpTransport.call(SOAPACTION, envelope);
        SoapObject response = (SoapObject) envelope.getResponse();

RunTimeException：无法序列化：通过ksoap将字节数组从android发送到java应用程序时出错

2 个答案: