glib2实际上是否泄漏了ALWAYS-MALLOC?

时间:2012-09-12 13:16:14

标签: c memory-leaks valgrind glib

此问题与许多其他人重复,因为我执行使用G_DEBUG=gc-friendlyG_SLICE=always-malloc 这是源代码:

#include <glib.h>

int main (int argc, char *argv[])
{
    GHashTable *ht;
    ht=g_hash_table_new(g_str_hash,g_str_equal);
    g_hash_table_insert(ht,"foo","bar");
    g_hash_table_destroy(ht);
    return 0;
}

以下是valgrind在此代码上的输出:

# G_DEBUG=gc-friendly G_SLICE=always-malloc valgrind --leak-check=full --show-reachable=yes ./test_vg
==1880== Memcheck, a memory error detector
==1880== Copyright (C) 2002-2010, and GNU GPL'd, by Julian Seward et al.
==1880== Using Valgrind-3.6.0 and LibVEX; rerun with -h for copyright info
==1880== Command: ./test_vg
==1880==
==1880==
==1880== HEAP SUMMARY:
==1880==     in use at exit: 1,260 bytes in 3 blocks
==1880==   total heap usage: 5 allocs, 2 frees, 1,524 bytes allocated
==1880==
==1880== 252 bytes in 1 blocks are still reachable in loss record 1 of 3
==1880==    at 0x4A04A28: calloc (vg_replace_malloc.c:467)
==1880==    by 0x35C8241707: g_malloc0 (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C8255742: ??? (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C825669D: g_slice_alloc (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C822B1D2: g_hash_table_new_full (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x400671: main (in /home/data/test_vg)
==1880==
==1880== 504 bytes in 1 blocks are still reachable in loss record 2 of 3
==1880==    at 0x4A04A28: calloc (vg_replace_malloc.c:467)
==1880==    by 0x35C8241707: g_malloc0 (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C8255722: ??? (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C825669D: g_slice_alloc (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C822B1D2: g_hash_table_new_full (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x400671: main (in /home/data/test_vg)
==1880==
==1880== 504 bytes in 1 blocks are still reachable in loss record 3 of 3
==1880==    at 0x4A04A28: calloc (vg_replace_malloc.c:467)
==1880==    by 0x35C8241707: g_malloc0 (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C825578B: ??? (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C825669D: g_slice_alloc (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x35C822B1D2: g_hash_table_new_full (in /lib64/libglib-2.0.so.0.2200.5)
==1880==    by 0x400671: main (in /home/data/test_vg)
==1880==
==1880== LEAK SUMMARY:
==1880==    definitely lost: 0 bytes in 0 blocks
==1880==    indirectly lost: 0 bytes in 0 blocks
==1880==      possibly lost: 0 bytes in 0 blocks
==1880==    still reachable: 1,260 bytes in 3 blocks
==1880==         suppressed: 0 bytes in 0 blocks
==1880==
==1880== For counts of detected and suppressed errors, rerun with: -v
==1880== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 6 from 6)

是内存泄漏吗?

3 个答案:

答案 0 :(得分:1)

我总是遇到很多错误和无法访问的问题 使用Valgrind检查GLIB2程序时的项目。在你的情况下, 泄漏似乎来自哈希表的创建。我会 创建第二个哈希表,看看是否有其他块 (否则,它可能是glib中的一些内部初始化)。

使用Valgrind与GLIB和GTK的一些注意事项在wiki.gnome.org

答案 1 :(得分:1)

回答你的问题:不,这不是传统意义上的内存泄漏。你的代码很好。

即使您使用G_DEBUG=gc-friendlyG_SLICE=always-malloc,GLib始终会离开&#34;仍然可以访问&#34;退出时的记忆。不要使用--show-reachable=yes选项,否则在使用GLib时,您将始终拥有污染的Valgrind输出。但是,如果你分配了在静态或全局变量中保留指针的内存(&#34;仍然可以访问&#34;内存),请小心。在这种情况下,你最终可能会忽略自己的&#34;真实&#34;泄漏。

答案 2 :(得分:0)

尝试将--suppressions=/usr/share/glib-2.0/valgrind/glib.supp传递到valgrind。它可以抑制来自GLib的误报。