我编写了一个简单的Web服务，它在JSONText中获取产品列表，它是字符串对象
Web服务代码在
之下using System;
using System.Collections.Generic;
using System.Web;
using System.Web.Services;
using System.Web.Script.Services;
using System.Runtime.Serialization.Json;
using System.IO;
using System.Text;
/// <summary>
/// Summary description for JsonWebService
/// </summary>
[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
[System.Web.Script.Services.ScriptService]
public class JsonWebService : System.Web.Services.WebService
{
public JsonWebService () {
//Uncomment the following line if using designed components
//InitializeComponent();
}
[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public string GetProductsJson(string prefix)
{
List<Product> products = new List<Product>();
if (prefix.Trim().Equals(string.Empty, StringComparison.OrdinalIgnoreCase))
{
products = ProductFacade.GetAllProducts();
}
else
{
products = ProductFacade.GetProducts(prefix);
}
//yourobject is your actula object (may be collection) you want to serialize to json
DataContractJsonSerializer serializer = new DataContractJsonSerializer(products.GetType());
//create a memory stream
MemoryStream ms = new MemoryStream();
//serialize the object to memory stream
serializer.WriteObject(ms, products);
//convert the serizlized object to string
string jsonString = Encoding.Default.GetString(ms.ToArray());
//close the memory stream
ms.Close();
return jsonString;
}
}
现在它给了我下面的resoponse：
{“d”：“[{\”“ProductID \”：1，\“ProductName \”：\“产品1 \”}，{\“ProductID \”：2，\“ProductName \”：\“产品2 \“}，{\”ProductID \“：3，\”ProductName \“：\”产品3 \“}，{\”ProductID \“：4，\”ProductName \“：\”产品4 \“ }，{\“ProductID \”：5，\“ProductName \”：\“产品5 \”}，{\“ProductID \”：6，\“ProductName \”：\“产品6 \”}，{\ “ProductID \”：7，\“ProductName \”：\“产品7 \”}，{\“ProductID \”：8，\“ProductName \”：\“产品8 \”}，{\“ProductID \” ：9，\“ProductName \”：\“产品9 \”}，{\“ProductID \”：10，\“ProductName \”：\“产品10 \”}]“}
但我正在寻找下面的
[{“ProductID”：1，“ProductName”：“Product 1”}，{“ProductID”：2，“ProductName”：“Product 2”}，{“ProductID”：3，“ProductName”：“产品3“}，{”ProductID“：4，”ProductName“：”产品4“}，{”ProductID“：5，”ProductName“：”产品5“}，{”ProductID“：6，”ProductName“： “产品6”}，{“ProductID”：7，“ProductName”：“产品7”}，{“ProductID”：8，“ProductName”：“产品8”}，{“ProductID”：9，“ProductName” ：“Product 9”}，{“ProductID”：10，“ProductName”：“Product 10”}]
任何人都可以告诉我什么是实际问题
由于
答案 0 :(得分：8)
首先，出于安全原因，ASP.NET 3.5发生了变化，Microsoft在响应中添加了“d”。以下是来自Encosia的Dave Ward的链接，其中讨论了您所看到的内容： A breaking change between versions of ASP.NET AJAX。他有几个帖子谈到这个可以帮助你进一步处理JSON和ASP.NET
答案 1 :(得分：0)
实际上，如果您只是删除
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
从该方法中，您返回使用JavaScriptSerializer序列化的 jsonString ，您将获得您正在寻找的输出。
答案 2 :(得分：0)
请注意，你的响应中你的ur数组旁边有双引号。这样你从ur web方法返回json格式而不是json对象.Json格式是一个字符串。因此你必须按顺序使用json.parse（）函数将json字符串解析为json对象。如果你不想使用解析函数，你必须删除ur web方法中的序列化。因此你得到一个json对象。
答案 3 :(得分：-1)
[WebMethod]
public string Android_DDD(string KullaniciKey, string Durum, string PersonelKey)
{
return EU.EncodeToBase64("{\"Status\":\"OK\",\"R\":[{\"ImzaTipi\":\"Paraf\", \"Personel\":\"Ali Veli üğişçöıÜĞİŞÇÖI\", \"ImzaDurumTipi\":\"Tamam\", \"TamamTar\":\"1.1.2003 11:21\"},{\"ImzaTipi\":\"İmza\", \"Personel\":\"Ali Ak\", \"ImzaDurumTipi\":\"Tamam\", \"TamamTar\":\"2.2.2003 11:21\"}]}");
}
static public string EncodeToBase64(string toEncode)
{
UTF8Encoding encoding = new UTF8Encoding();
byte[] bytes = encoding.GetBytes(toEncode);
string returnValue = System.Convert.ToBase64String(bytes);
return returnValue;
}
在android
中 private static String convertStreamToString(InputStream is)
{
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try
{
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
}
catch (IOException e)
{
e.printStackTrace();
}
finally
{
try
{
is.close();
}
catch (IOException e)
{
e.printStackTrace();
}
}
return sb.toString();
}
private void LoadJsonDataFromASPNET()
{
try
{
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httpPostRequest = new HttpPost(this.WSURL + "/WS.asmx/Android_DDD");
JSONObject jsonObjSend = new JSONObject();
jsonObjSend.put("KullaniciKey", "value_1");
jsonObjSend.put("Durum", "value_2");
jsonObjSend.put("PersonelKey", "value_3");
StringEntity se = new StringEntity(jsonObjSend.toString());
httpPostRequest.setEntity(se);
httpPostRequest.setHeader("Accept", "application/json");
httpPostRequest.setHeader("Content-type", "application/json");
// httpPostRequest.setHeader("Accept-Encoding", "gzip"); // only set this parameter if you would like to use gzip compression
HttpResponse response = (HttpResponse) httpclient.execute(httpPostRequest);
HttpEntity entity = response.getEntity();
if (entity != null)
{
InputStream instream = entity.getContent();
String resultString = convertStreamToString(instream);
instream.close();
resultString = resultString.substring(6, resultString.length()-3);
resultString = new String(android.util.Base64.decode(resultString, 0), "UTF-8");
JSONObject object = new JSONObject(resultString);
String oDurum = object.getString("Status");
if (oDurum.equals("OK"))
{
JSONArray jsonArray = new JSONArray(object.getString("R"));
if (jsonArray.length() > 0)
{
for (int i = 0; i < jsonArray.length(); i++)
{
JSONObject jsonObject = jsonArray.getJSONObject(i);
String ImzaTipi = jsonObject.getString("ImzaTipi");
String Personel = jsonObject.getString("Personel");
String ImzaDurumTipi = jsonObject.getString("ImzaDurumTipi");
String TamamTar = jsonObject.getString("TamamTar");
Toast.makeText(getApplicationContext(), "ImzaTipi:" + ImzaTipi + " Personel:" + Personel + " ImzaDurumTipi:" + ImzaDurumTipi + " TamamTar:" + TamamTar, Toast.LENGTH_LONG).show();
}
}
}
}
}
catch (Exception e)
{
e.printStackTrace();
}
}