Question

我在表中有超过1行属于同一个ID。

我想选择更多列包含数据的行。

例如

我的数据看起来像这样

select * from my_table where id=1

PK   Id   Col1   Col2   Col3   Col4   Col5   Col6   Col7   Col8   Col9   Col10
101  1    NULL   NULL   NULL   XX     NULL   NULL   NULL   NULL   NULL   NULL
102  1    NULL   NULL   NULL   XX     YY     NULL   ZZ     NULL   NULL   NULL
103  1    NULL   AA     NULL   NULL   NULL   NULL   NULL   NULL   NULL   NULL
104  1    NULL   NULL   NULL   NULL   NULL   BB     NULL   NULL   NULL   NULL
105  1    NULL   NULL   NULL   NULL   NULL   NULL   NULL   CC     NULL   NULL

我想查询哪个会给我这样的输出id = 1： -

PK   Id   Col1   Col2   Col3   Col4   Col5   Col6   Col7   Col8   Col9   Col10
102  1    NULL   NULL   NULL   XX     YY     NULL   ZZ     NULL   NULL   NULL

Answer 1

pk是你的主要关键......

select * 
from YourBadlyStructuredTable
where pk in (
    select top 1 pk from YourBadlyStructuredTable
    unpivot (col for z in (col1,col2,col3, ...))u
    where id=1
    group by pk
    order by COUNT(*) desc
)

如果您无法指定列名...

select 
    top 1 
    HorribleTable.* 
from
(
    select
        xmldata.value('(/x2/@PK)[1]','int') as PK1,
        xmldata.value('(/x2/@Id)[1]','int') as ID1,
        xmldata.value('count(/x2/@*)','int') as cnt
        from
        (
    select      
        t.x.query('.') as xmldata               
    from
        (   select convert(xml,(select * from HorribleTable for xml raw('x2'))) as x1) v
            cross apply
        v.x1.nodes('/x2') t(x)
    ) v
) v
    inner join HorribleTable on v.PK1 = HorribleTable.pk
where ID1 = 1 
order by cnt desc

Answer 2

试试这个：

with cte as (select  *,case when col1 is not null then 1 else 0 end+
          case when col2 is not null then 1 else 0 end+
          case when col3 is not null then 1 else 0 end+
          case when col4 is not null then 1 else 0 end+
          case when col5 is not null then 1 else 0 end+
          case when col6 is not null then 1 else 0 end+
          case when col7 is not null then 1 else 0 end+
          case when col8 is not null then 1 else 0 end+
          case when col9 is not null then 1 else 0 end+
          case when col10 is not null then 1 else 0 end as col_count
  from my_table  where id=1)
  select * from cte where col_count =(select MAX(col_count) from cte)

Answer 3

;WITH CTE as (    
select pk,isnull(col1,'')+isnull(col2,'')+isnull(col3,'')+isnull(col4,'')+isnull(col5,'')+
    isnull(col6,'')+isnull(col7,'')+isnull(col8,'')+isnull(col9,'')+isnull(col10,'') as res
    from tbl4 where id=1)


select * from tbl4 where pk in(select pk from CTE where len(res)=(select max(len(res)) from CTE))

选择具有最大列数据的行

3 个答案: