我有一个包含二进制和字符串字符的字符串,我想先将其转换为二进制,然后转换为十六进制。
字符串如下:
<81>^Q<81>"^Q^@^[)^G ^Q^A^S^A^V^@<83>^Cd<80><99>}^@N^@^@^A^@^@^@^@^@^@^@j
如何在Python中转换此字符串,以便十六进制格式的输出与此类似?
24208040901811001B12050809081223431235113245422F0A23000000000000000000001F
答案 0 :(得分:24)
您可以像这样使用ord和hex:
>>> s = 'some string'
>>> hex_chars = map(hex,map(ord,s))
>>> print hex_chars
['0x73', '0x6f', '0x6d', '0x65', '0x20', '0x73', '0x74', '0x72', '0x69', '0x6e', '0x67']
>>> hex_string = "".join(c[2:4] for c in hex_chars)
>>> print hex_string
736f6d6520737472696e67
>>>
或使用内置编码:
>>> s = 'some string'
>>> print s.encode('hex_codec')
736f6d6520737472696e67
>>>
答案 1 :(得分:9)
>>> import binascii
>>> s = '2F'
>>> hex_str = binascii.b2a_hex(s)
>>> hex_str
>>> '3246'
OR
>>>import binascii
>>> hex_str = binascii.hexlify(s)
>>> hex_str
>>> '3246'
>>>
答案 2 :(得分:1)
更快的解决方案见:
from timeit import Timer
import os
import binascii
def testSpeed(statement, setup = 'pass'):
print '%s' % statement
print '%s' % Timer(statement, setup).timeit()
setup = """
import os
value = os.urandom(32)
"""
# winner
statement = """
import binascii
binascii.hexlify(value)
"""
testSpeed(statement, setup)
# loser
statement = """
import binascii
value.encode('hex_codec')
"""
testSpeed(statement, setup)
结果:
import binascii
binascii.hexlify(value)
2.18547999816
value.encode('hex_codec')
2.91231595077