我正在编写一个程序来根据用户的输入(名字,中间名和姓氏)生成用户名。我应该从每个名字(第一个,中间个和最后一个)获取第一个字符以及姓氏的最后一个字符以生成用户名。我已成功编写程序来生成每个名称的第一个字符,但是当我试图让我的程序生成姓氏的最后一个字符时,我会收到此错误:
线程“main”中的异常java.lang.StringIndexOutOfBoundsException:字符串索引超出范围:7
at java.lang.String.charAt(String.java:658)
at UsernameGenerator.main(UsernameGenerator.java:39)
这是我的代码:
import java.util.Scanner;
/**
UsernameGenerator.java
Generates a username based on the users inputs.
@author: Evan Fravert
*/
public class UsernameGenerator {
/**
* Generates a username based on the users inputs.
*@param args command line argument
*/
public static void main(String[] args)
{ // abcde
String first;
String middle;
String last;
String password1;
String password2;
int randomNum;
randomNum = (int) (Math.random() * 1000) + 100;
Scanner userInput = new Scanner(System.in);
System.out.println("Please enter your first name:");
first = userInput.nextLine();
String firstLower = first.toLowerCase();
System.out.println("Please enter your middle name:");
middle = userInput.nextLine();
String middleLower = middle.toLowerCase();
System.out.println("Please enter your last name:");
last = userInput.nextLine();
int lastEnd = last.length();
String lastLower = last.toLowerCase();
System.out.println("Please enter your password:");
password1 = userInput.nextLine();
System.out.println("Please enter your password again:");
password2 = userInput.nextLine();
char firstLetter = firstLower.charAt(0);
char middleLetter = middleLower.charAt(0);
char lastLetter = lastLower.charAt(0);
char lastLast = lastLower.charAt(lastEnd);
if (first == null || first.length() <= 0) {
firstLetter = 'z';
}
else {
firstLetter = firstLower.charAt(0);
}
System.out.println("Your username is " + firstLetter + ""
+ middleLetter + "" + lastLetter + "" + "" + lastLast + "" + randomNum);
System.out.println("Your password is " + password1);
System.out.println("Welcome " + first + " " + middle + " " + last + "!");
}
}
提前致谢!
答案 0 :(得分:4)
Java数组基于零,最后一个索引是last.length() - 1
答案 1 :(得分:1)
试试这个:
char lastLast = lastLower.charAt(lastEnd-1);