这是对此问题的跟进:count number of foreign keys
我正在使用doctrine 1.2,我想计算属于子类别的业务数量。
以下是mysql表。
1。fi_category
+----+-----------------+-----------------+
| id | name | slug |
+----+-----------------+-----------------+
2。fi_subcategory
+----+-----------------+-----------------+-------------+
| id | name | slug | category_id |
+----+-----------------+-----------------+-------------+
第3。fi_business_subcategory
+----+-------------+----------------+
| id | business_id | subcategory_id |
+----+-------------+----------------+
我正在使用这个DQL。
$q = Doctrine_Query::create()
->select('c.name, c.slug, sc.name, sc.slug')
->from('Model_Category c')
->leftJoin('c.Subcategory sc')
->leftJoin('sc.BusinessSubcategory bsc');
这给了我这样的东西。
Array
(
[0] => Array
(
[id] => 1
[name] => Entertainment & Lifestyle
[slug] => entertainment-lifestyle
[Subcategory] => Array
(
[0] => Array
(
[id] => 1
[name] => Arts and Crafts
[slug] => arts-and-crafts
)
[1] => Array
(
[id] => 2
[name] => Family
[slug] => family
)
[2] => Array
(
[id] => 3
[name] => Fashion
[slug] => fashion
)
)
)
)
我希望获取业务数量,即返回的结果应该是这样的,具体取决于它所属的业务。
Array
(
[0] => Array
(
[id] => 1
[name] => Entertainment & Lifestyle
[slug] => entertainment-lifestyle
[Subcategory] => Array
(
[0] => Array
(
[id] => 1
[name] => Arts and Crafts
[slug] => arts-and-crafts
[business_count] => 35
)
[1] => Array
(
[id] => 2
[name] => Family
[slug] => family
[business_count] => 10
)
[2] => Array
(
[id] => 3
[name] => Fashion
[slug] => fashion
[business_count] => 27
)
)
)
)
尝试使用DQL的各种方法,但似乎没有任何结果。知道我该怎么做我想要的东西?
答案 0 :(得分:1)
你有没有尝试过:
$q = Doctrine_Query::create()
->select('c.name, c.slug, sc.name, sc.slug, COUNT(sc.BusinessSubcategory.id) AS business_count')
->from('Model_Category c')
->leftJoin('c.Subcategory sc')
->groupBy('c.id, sc.id');
HYDRATE_ARRAY