我有一个网络应用程序是一个游戏,只有在某些分数后,人们才能成为朋友,并且应该自动添加到彼此的朋友列表中。
试图弄清楚如何处理Ejabberd中的名单
使用类似strophe的客户端JS库不安全我需要使用serveride方法将用户添加到彼此的名单中。关于如何用Ejabberd做这个想法的想法?
编辑: 好吧,似乎ejabberd的mod_rest给了restfull访问(所有?)ejabbard方法
答案 0 :(得分:0)
好的,所以在我走上正确的轨道后,我设法在一小时内搞清楚了......
命令:
ejabberdctl help process_rosteritems
:
Command Name: process_rosteritems
Arguments: action::string
subs::string
asks::string
users::string
contacts::string
Returns: res::rescode
Tags: roster
Description: List or delete rosteritems that match filtering options
Explanation of each argument:
- action: what to do with each rosteritem that matches all the filtering options
- subs: subscription type
- asks: pending subscription
- users: the JIDs of the local user
- contacts: the JIDs of the contact in the roster
Allowed values in the arguments:
ACTION = list | delete
SUBS = SUB[:SUB]* | any
SUB = none | from | to | both
ASKS = ASK[:ASK]* | any
ASK = none | out | in
USERS = JID[:JID]* | any
CONTACTS = JID[:JID]* | any
JID = characters valid in a JID, and can use the globs: *, ?, ! and [...]
This example will list roster items with subscription 'none', 'from' or 'to' that have any ask property, of local users which JID is in the virtual host 'example.org'
and that the contact JID is either a bare server name (without user part) or that has a user part and the server part contains the word 'icq':
list none:from:to any *@example.org *:*@*icq*