Question

我有以下QString，我只想提取access_token值，即＆＃34; http％3a％2f％2fschemas.xmlsoap .....＆＃34;怎么做？

{＆＃34; token_type＆＃34;：＆＃34; HTTP：//schemas.xmlsoap.org/ws/2009/11/swt-token-profile-1.0"，＆＃34;＆的access_token ＃34;：＆＃34; HTTP％3A％2F％2fschemas.xmlsoap.org％2fws％2f2005％2f05％2fidentity％2fclaims％2fnameidentifier = asdasr21321214a％2F％2fschemas.microsoft.com％2faccwresscontrolservice％2f2010％2f07％2fclaims％ 2fidentityprovider = HTTPS％3A％2F％2fdatamarket.accesscontrol.windows.net％2F＆安培;观众= HTTP％3A％2F％2fapi.microsofttranslator.com＆安培; ExpiresOn = 1347332993＆安培;发行人= HTTPS％3A％2F％2fdatamarket.accesscontrol.windows。净％2F＆安培; HMACSHA256 = sFqvp2a2xXc3VBdxYZ6xHQf％2fKkOydnuX6VK7A6Yf55k％3D＆＃34;＆＃34; expires_in＆＃34;：＆＃34; 599＆＃34;＆＃34;范围＆＃34;：＆＃34; HTTP：// api.microsofttranslator.com＆＃34;}

Answer 1

在http://qjson.sourceforge.net/查看QJson。

您可以轻松地将字符串解析为标记化属性。从使用页面：

QJson::Parser parser;
QString json = "{your json above}";
bool ok;
QVariant result = parser.parse (json, &ok);
qDebug() << result["access_token"].toString();

玩得开心。

Answer 2

试试这个正则表达式：

\"access_token\":\"([^\"]*)\"

解释

<强> ( subexpression )
Captures the matched subexpression and assigns it a zero-based ordinal number.

<强> [^ character_group ]
Negation: Matches any single character that is not in character_group. By default, characters in character_group are case-sensitive.

Answer 3

快速又脏，仅用于演示QString :: section：

QString Data("{...you json data...}");
QString AccessToken = data.section("access_token\":\"",1).section("\"",0,0);

考虑：QString :: section缓慢而且很重，创建QStringList并在后台将tokens转换为RegExp。但在某些情况下我仍经常使用它。

提取特定字符串

3 个答案: