我正在尝试学习各种模拟库的来龙去脉,PowerMock(特别是EasyMock扩展名)是下一个列表。我试图模拟一个构造函数,当我尝试复制它们时,提供的示例没有相同的响应。据我所知,它从不嘲笑构造函数,只是继续进行,就好像它是正常的一样。
这是测试类:
@RunWith(PowerMockRunner.class)
@PrepareForTest({Writer.class})
public class FaultInjectionSituationTest {
@Test
public void testActionFail() throws Exception {
FaultInjectionSituation fis = new FaultInjectionSituation();
PowerMock.expectNew(Writer.class, "test")
.andThrow(new IOException("thrown from mock"));
PowerMock.replay(Writer.class);
System.out.println(fis.action());
PowerMock.verify(Writer.class);
}
}
我尝试用EasyMock.isA(String.class)替换“test”,但它产生了相同的结果。
这是FaultInjectionSituation:
public class FaultInjectionSituation {
public String action(){
Writer w;
try {
w = new Writer("test");
} catch (IOException e) {
System.out.println("thrown: " + e.getMessage());
return e.getLocalizedMessage();
}
return "returned without throw";
}
}
“作家”只不过是一个类的外壳:
public class Writer {
public Writer(String s) throws IOException {
}
public Writer() throws IOException{
}
}
当测试运行时,它会打印出“return without throw”,表示从未抛出异常。
答案 0 :(得分:22)
你需要准备正在调用构造函数的类,因此PowerMock知道期望一个模拟的构造函数调用。尝试使用以下代码更新代码:
@RunWith(PowerMockRunner.class)
@PrepareForTest({Writer.class, FaultInjectionSituation.class})
public class FaultInjectionSituationTest {
// as before
}
答案 1 :(得分:1)
您需要先创建一个模拟对象:
Writer mockWriter = PowerMock.createMock(Writer.class)
PowerMock.expectNew(Writer.class, "test").andReturn(mockWriter)