Question

我试图在for循环中添加两个浮点数，它告诉我＆＃39; +＆＃39;没有影响。我试图让它解析两个范围的每个增量（.25）（生成和结束）（1和2）和1 + .25不能正常工作，我得到一个无限循环

float begrate,endrate,inc,year=0;

cout << "Monthly Payment Factors used in Compute Monthly Payments!" << endl;
cout << "Enter Interest Rate Range and Increment" << endl;
cout << "Enter the Beginning of the Interest Range:  ";
cin >> begrate;
cout << "Enter the Ending of the Interest Range:  ";
cin >> endrate;
cout << "Enter the Increment of the Interest Range:  ";
cin >> inc;
cout << "Enter the Year Range in Years:  ";
cin >> year;

cout << endl;

for (float i=1;i<year;i++){
    cout << "Year:  " << "     ";
    for(begrate;begrate<endrate;begrate+inc){
        cout << "Test " << begrate << endl;
    }
}
system("pause");
return 0;

Answer 1

那是因为begrate + inc对begrate的值没有影响。 +运算符与++运算符不同。您必须将结果分配给具有效果的内容。你想要的是：

begrate = begrate + inc

或者

begrate += inc

Answer 2

您可以使用+ =代替+，因为这会将begrate设置为begrate+inc。更好的解决方案是使一个临时循环变量开始等于生成然后递增它。

for (float i=1;i<year;i++){
    cout << "Year:  " << "     ";
    for(float j = begrate;j<endrate;j+=inc){
        cout << "Test " << j << endl;
    }
}

Answer 3

Just replace the following line

for(begrate;begrate<endrate;begrate+inc){


with

for(begrate;begrate<endrate;begrate+=inc){

请注意这里的生命* + = * inc

加法运算符没有影响

3 个答案: