使用一个语句更新mysql中的两个表

时间:2012-09-10 16:09:42

标签: mysql sql-update multi-table

我有两张桌子 - “活动”和“房间”。

房间表如下:

    CREATE TABLE `rooms` (
    `roomKey` INT(9) UNSIGNED NOT NULL AUTO_INCREMENT,
    `locationID` INT(9) NOT NULL DEFAULT '0',
    `locationName` VARCHAR(150) NOT NULL DEFAULT '',
    `buildingID` INT(9) NOT NULL DEFAULT '0',
    `buildingName` VARCHAR(150) NOT NULL DEFAULT '',
    `areaID` INT(9) NOT NULL DEFAULT '0',
    `areaName` VARCHAR(150) NOT NULL DEFAULT '',
    `roomID` INT(9) NOT NULL DEFAULT '0',
    `roomName` VARCHAR(150) NOT NULL DEFAULT '',
    `clientKey` MEDIUMINT(5) UNSIGNED NOT NULL DEFAULT '0',
    PRIMARY KEY (`roomKey`),
    UNIQUE INDEX `locationID` (`locationID`, `buildingID`, `areaID`, `roomID`, `clientKey`),
    INDEX `clientKey` (`clientKey`)

)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
AUTO_INCREMENT=21270411;

并且事件表如下所示:

CREATE TABLE `events` (
    `eventKey` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT,
    `accountNum` INT(11) NULL DEFAULT NULL,
    `locationID` INT(9) NOT NULL DEFAULT '0',
    `buildingID` INT(9) NOT NULL DEFAULT '0',
    `areaID` INT(9) NOT NULL DEFAULT '0',
    `roomID` INT(9) NOT NULL DEFAULT '0',
    `clientKey` SMALLINT(5) UNSIGNED NOT NULL,
    `roomKey` INT(10) UNSIGNED NOT NULL DEFAULT '0',
    `eventTitle` VARCHAR(100) NOT NULL DEFAULT '',
    `dateStart` DATETIME NOT NULL DEFAULT '0000-00-00 00:00:00',
    `dateEnd` DATETIME NOT NULL DEFAULT '0000-00-00 00:00:00',
    `status` SMALLINT(5) UNSIGNED NOT NULL DEFAULT '0',
    PRIMARY KEY (`eventKey`),
    UNIQUE INDEX `uniqueEvent` (`accountNum`, `locationID`, `buildingID`, `areaID`, `roomID`),
    INDEX `clientKey` (`clientKey`)
)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
AUTO_INCREMENT=98690419;

有一个过程会将新事件的批量导入插入到事件表中。一旦完成,我们需要使用与“rooms”表中的主键对应的roomKey更新新记录 - 我们可以使用房间中记录的locationID,buildingID,areaID,roomID和clientKey来匹配表。 (clientKey是必要的,因为多个帐户可以具有相同的位置,bldg,区域或房间值。)

目前,我使用的查询是:

UPDATE events e, rooms dr SET e.locationKey=dr.locationKey 
       WHERE e.locationID=dr.locationID 
           AND e.buildingID=dr.buildingID 
           AND e.areaID=dr.areaID 
           AND e.roomID=dr.roomID 
           AND e.clientKey=dr.clientKey

但它没有考虑两个帐户(客户)在location,bldg,area和room中具有相同值的情况。根据另一个帐户具有相同locationID,buildingID,areaID和roomID的房间记录这一事实,查询很容易将错误的roomKey值放入事件记录中。

我可以将查询修改为如下所示运行,但速度非常慢。我知道这不是正确的查询,因此我希望改进它 - 无需使用PHP循环等进行此更新。

UPDATE EVENTS e, rooms dr SET e.locationKey=dr.locationKey
WHERE (e.locationID=dr.locationID AND e.clientKey=dr.clientKey)
    AND (e.buildingID=dr.buildingID  AND e.clientKey=dr.clientKey)
    AND (e.areaID=dr.areaID  AND e.clientKey=dr.clientKey)
    AND (e.roomID=dr.roomID  AND e.clientKey=dr.clientKey)
    AND e.clientKey=dr.clientKey

2 个答案:

答案 0 :(得分:0)

在Mysql中,您可以在加入update

时使用此语法
UPDATE table1 t1 
       INNER JOIN table2 t2 
         ON t1.id = t2.id
SET t1.col1 = t2.col2, t1.col2 = t2.col2

答案 1 :(得分:0)

如果clientKey中的rooms值具有权威性,您只想根据匹配的clientKey值更新events中的所有roomID值,那么您应该能够做到这一点:

UPDATE rooms AS r
INNER JOIN events AS e ON r.roomKey = e.roomKey
SET e.clientKey = r.clientKey