Question

在简单的库存管理数据库中，添加并运送新库存的数量，直到数量达到零。每个库存移动都分配了一个参考，只使用最新的参考。

在提供的示例中，最新的引用从未显示过，股票ID的1,4应该分别有引用charlie，foxtrot，而是显示alpha，delta。

如何将多个条件上的GROUP BY和LEFT JOIN相关联以显示最新记录？

CREATE TABLE stock (
  id tinyint PRIMARY KEY,
  quantity int,
  parent_id tinyint
);

CREATE TABLE stock_reference (
  id tinyint PRIMARY KEY,
  stock_id tinyint,
  stock_reference_type_id tinyint,
  reference varchar(50)
);

CREATE TABLE stock_reference_type (
  id tinyint PRIMARY KEY,
  name varchar(50)
);

INSERT INTO stock VALUES 
(1, 10, 1),
(2, -5, 1),
(3, -5, 1),
(4, 20, 4),
(5, -10, 4),
(6, -5, 4);

INSERT INTO stock_reference VALUES 
(1, 1, 1, 'Alpha'),
(2, 2, 1, 'Beta'),
(3, 3, 1, 'Charlie'),
(4, 4, 1, 'Delta'),
(5, 5, 1, 'Echo'),
(6, 6, 1, 'Foxtrot');

INSERT INTO stock_reference_type VALUES 
(1, 'Customer Reference');

SELECT stock.id, SUM(stock.quantity) as quantity, customer.reference
FROM stock
LEFT JOIN stock_reference AS customer ON stock.id = customer.stock_id AND stock_reference_type_id = 1
GROUP BY stock.parent_id

Answer 1

您可以使用子查询为每个股票组提取最新的ID：

SELECT g.parent_id, g.quantity, customer.reference
FROM (
    SELECT parent_id, SUM(stock.quantity) as quantity, MAX(id) as LatestID
    FROM stock
    GROUP BY parent_id
) g LEFT JOIN stock_reference AS custome
    ON g.LatestID = customer.stock_id AND stock_reference_type_id = 1

在多个标准上关联GROUP BY和LEFT JOIN以显示最新记录？

1 个答案: