我为 SQL Server 中的表创建了一个触发器,它对我有用。
我的问题是:如何找到并修改它?
我使用此查询来查找触发器:
select * from sys.triggers
这可以找到所有触发器,但是如何打开它并更改触发器?
答案 0 :(得分:45)
您只需使用SSMS即可完成此操作。只需转到表名并展开“触发器”节点,即可查看与该表关联的触发器列表。右键单击以修改触发器。
答案 1 :(得分:34)
select so.name, text
from sysobjects so, syscomments sc
where type = 'TR'
and so.id = sc.id
and text like '%YourTableName%'
通过这种方式,您可以列出与给定表关联的所有触发器。
答案 2 :(得分:9)
这可能很有用
SELECT
t.name AS TableName,
tr.name AS TriggerName
FROM sys.triggers tr
INNER JOIN sys.tables t ON t.object_id = tr.parent_id
WHERE
t.name in ('TABLE_NAME(S)_GOES_HERE');
这样你只需要插入表名,查询就会获取你需要的所有触发器
答案 3 :(得分:6)
select m.definition from sys.all_sql_modules m inner join sys.triggers t
on m.object_id = t.object_id
这里只需复制定义并更改触发器。
此外,您可以转到SSMS并展开您的数据库,然后在Programmability下展开Database Triggeres,然后右键单击特定触发器并单击修改,您也可以更改。
答案 4 :(得分:5)
使用sp_helptrigger查找关联表的触发器列表
答案 5 :(得分:3)
在桌面上查找触发器:
select so.name, text
from sysobjects so, syscomments sc
where type = 'TR'
and so.id = sc.id
and text like '%TableName%'
你可以找到参考表的商店程序:
SELECT Name
FROM sys.procedures
WHERE OBJECT_DEFINITION(OBJECT_ID) LIKE '%yourtablename%'
答案 6 :(得分:2)
使用此查询,您可以在所有表和所有视图中找到所有触发器。
;WITH
TableTrigger
AS
(
Select
Object_Kind = 'Table',
Sys.Tables.Name As TableOrView_Name ,
Sys.Tables.Object_Id As Table_Object_Id ,
Sys.Triggers.Name As Trigger_Name,
Sys.Triggers.Object_Id As Trigger_Object_Id
From Sys.Tables
INNER Join Sys.Triggers On ( Sys.Triggers.Parent_id = Sys.Tables.Object_Id )
Where ( Sys.Tables.Is_MS_Shipped = 0 )
),
ViewTrigger
AS
(
Select
Object_Kind = 'View',
Sys.Views.Name As TableOrView_Name ,
Sys.Views.Object_Id As TableOrView_Object_Id ,
Sys.Triggers.Name As Trigger_Name,
Sys.Triggers.Object_Id As Trigger_Object_Id
From Sys.Views
INNER Join Sys.Triggers On ( Sys.Triggers.Parent_id = Sys.Views.Object_Id )
Where ( Sys.Views.Is_MS_Shipped = 0 )
),
AllObject
AS
(
SELECT * FROM TableTrigger
Union ALL
SELECT * FROM ViewTrigger
)
Select
*
From AllObject
Order By Object_Kind, Table_Object_Id
答案 7 :(得分:0)
下面的简单查询
select (select [name] from sys.tables where [object_id] = tr.parent_id ) as TableName ,* from sys.triggers tr
答案 8 :(得分:0)
从information_schema.TRIGGERS中选择*;
答案 9 :(得分:0)
select t.name as TriggerName,m.definition,is_disabled
from sys.all_sql_modules m
inner join
sys.triggers t
on m.object_id = t.object_id
inner join sys.objects o
on o.object_id = t.parent_id
Where o.name = 'YourTableName'
这将为您提供指定表
上的所有触发器答案 10 :(得分:0)
您可以通过以下查询查看与数据库相关的所有触发器
select * from sys.triggers
对于开放式触发器,您可以使用以下语法
sp_helptext 'dbo.trg_InsertIntoUserTable'
答案 11 :(得分:0)
尝试使用:
select * from sys.objects where type='tr' and name like '%_Insert%'
答案 12 :(得分:0)
您可以使用以下命令打开触发器 sp_helptext yourtriggername
答案 13 :(得分:0)
select o1.name as trigger_name,o2.name as table_name from sys.objects o1
join sys.objects o2 on
o1.parent_object_id=o2.object_id
where o1.type='TR'
and o2.name='my_table'
答案 14 :(得分:0)
select B.name
from sys.objects A
join sys.triggers B
on A.object_id = B.parent_id
where A.name ='Table_name' /*Table Name*/