Question

我有使用curl上传文件的问题。我想在视频托管网站上传我的服务器文件。脚本需要Content-type: multipart/form-data和Content-type: video/mp4，但我不知道如何做到这一点。上传后，文件包含content type application/octet-stream。

这是脚本

class curl
{
         function __construct($use = 1)
         {
         $this->ch = curl_init();
                 if($use = 1)
                 {
                         curl_setopt ($this->ch, CURLOPT_POST, 1);
                         curl_setopt ($this->ch, CURLOPT_COOKIEJAR, 'cookie.txt');
                         curl_setopt ($this->ch, CURLOPT_FOLLOWLOCATION, 1);
                         curl_setopt ($this->ch, CURLOPT_RETURNTRANSFER, 1);
                 }
                 else
                 {
                         return 'There is the possibility, that this script wont work';
                 }
         }
         function first_connect($loginform,$logindata)
         {
                 curl_setopt($this->ch, CURLOPT_URL, $loginform);
                 curl_setopt($this->ch, CURLOPT_POSTFIELDS, $logindata);
         }
         function store()
         {
                 $this->content = curl_exec ($this->ch);
         }
         function execute($page)
         {
                 curl_setopt($this->ch, CURLOPT_URL, $page);
                 $this->content = curl_exec ($this->ch);
         }
         function close()
         {
                 curl_close ($this->ch);
         }

         function __toString()
         {
         return $this->content;
         }

         function upload($file)
         {
            curl_setopt($this->ch, CURLOPT_HTTPHEADER, array("Content-type: multipart/form-data"));
            curl_setopt($this->ch, CURLOPT_URL, 'http://uploadsite.com/index.php?act=files&do=upload');
            $postdata = array("file[]" => "@/".realpath($file));
            echo $postdata;
            curl_setopt($this->ch, CURLOPT_POSTFIELDS, $postdata);
            curl_exec ($this->ch);
         }
}


$getit = new curl();
$getit->first_connect('http://uploadsite.com/index.php?act=login&login=true','login=true&file_session=&email=xxx%40yahoo.de&password=xxx&upload=Login');
$getit->store();
$getit->execute('http://uploadsite.com/index.php?act=user&do=home');
$getit->upload('Sample.mp4');

来自livehttpheaders

的套餐

http://uploadsite.com/index.php?act=files&do=upload

POST /index.php?act=files&do=upload HTTP/1.1
Host: yourupload.com
User-Agent: Mozilla/5.0 (Windows NT 6.1; rv:15.0) Gecko/20100101 Firefox/15.0.1
Accept: text/javascript, text/html, application/xml, text/xml, */*
Accept-Language: de-de,de;q=0.8,en-us;q=0.5,en;q=0.3
Accept-Encoding: gzip, deflate
Connection: keep-alive
X-Requested-With: XMLHttpRequest
Referer: http://yourupload.com/index.php?act=user&do=home
Content-Length: 41648931
Content-Type: multipart/form-data; boundary=---------------------------265001916915724
Cookie: _pk_ref.9.d1ba=%5B%22%22%2C%22%22%2C1347200605%2C%22http%3A%2F%2F62.75.242.162%2Findex.php%22%5D; _pk_id.9.d1ba=08e499ca1b88c81c.1345157523.12.1347203814.1347189831.; PHPSESSID=jjajqi2mi7fe1blso5qvge9ue5; _pk_ses.9.d1ba=*; member_id=3051; member_pass=xxx
Pragma: no-cache
Cache-Control: no-cache
-----------------------------265001916915724
Content-Disposition: form-data; name="file[]"; filename="Sample.mp4"
Content-Type: video/mp4


HTTP/1.1 200 OK
Server: nginx/0.7.67
Date: Sun, 09 Sep 2012 15:23:56 GMT
Content-Type: text/html
Transfer-Encoding: chunked
Connection: keep-alive
X-Powered-By: PHP/5.3.3-7+squeeze13
Expires: Thu, 19 Nov 1981 08:52:00 GMT
Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0
Pragma: no-cache

Answer 1

替换此行：

$postdata = array("file[]" => "@/".realpath($file));

使用：

$postdata = array("file[]" => "@/".realpath($file).";type=video/mp4");

它应该有用。

Answer 2

我使用curl连接Web服务并使用与此帖相似的想法上传文件，但它不起作用。与前一个答案不同的原因，所以我将描述我的解决方案;也许我的经历对其他人有用。

我有两个问题。第一个是我的Web服务不喜欢文件名中的绝对路径。如果OP代码中的$ file有路径，则使用：

$postdata = array('file[]' => "@/".realpath($file));

变为：

Content-Disposition: form-data; name="file[]"; filename="/tmp/iy56ham"

并且该路径生成了一个不良请求。所以我不得不使用chdir，basename和dirname以避免在$ postdata中使用路径。

另一方面，curl发送了一个额外的标题，未在OP中显示：

Expect: 100-continue

我的网络服务不喜欢它（既不是推特WS），也用它来回答：

417 Expectation Failed

为避免卷曲发送有问题的标题，您可以使用：

curl_setopt( $curlHandler, CURLOPT_HTTPHEADER, array('Expect:') );

所以你设置一个空的Expect标题，curl不会被100-continue覆盖。

希望这有助于某人...

使用multipart / form-data上传卷曲文件

2 个答案: