Question

嘿伙计们只是想把一些东西传递给我的控制器。使用codeigniter，下面的表单实际上并没有将我重定向到任何地方，这有什么不对？

我的第二个问题是如何在控制器中抓取数据只是一个简单的..？

$data = $this->input->$post('search');

<?php
$options = array(
                  'small'  => 'Small Shirt',
                  'med'    => 'Medium Shirt',
                  'large'   => 'Large Shirt',
                  'xlarge' => 'Extra Large Shirt',
                );

$shirts_on_sale = array('small', 'large');
echo form_dropdown('shirts', $options, 'large');

?>
 <form  action="<?php echo site_url('home/id_search');?>" method="post"><input type="submit" value="submit" id="" name="" >
</form>

Answer 1

您将表单开始标记放在错误的位置，执行：

 <form  action="<?php echo site_url('home/id_search');?>" method="post">
<?php
$options = array(
                  'small'  => 'Small Shirt',
                  'med'    => 'Medium Shirt',
                  'large'   => 'Large Shirt',
                  'xlarge' => 'Extra Large Shirt',
                );

$shirts_on_sale = array('small', 'large');
echo form_dropdown('shirts', $options, 'large');

?>
<input type="submit" value="submit" id="" name="btnSubmit" />
</form>

And to get POST date in you controller, do:
$data = $this->input->post('shirts'); //for getting shirts form field value

将表单变量传递给控制器

1 个答案: