从嵌入式Neo4j(蓝图)读取随机返回null

时间:2012-09-08 13:09:48

标签: scala playframework neo4j

我正在尝试解决Neo4j和蓝图的问题。添加顶点可以正常工作,也可以向它们添加属性。但是当我尝试从数据库中读取顶点时出现问题。它们都被读取 - 因此它们的数量是可以的,但它们随机地没有它们的属性和边缘。而不是他们我得到零。有点奇怪的是,当Vertex曾经有一个null属性时,另一次它有预期的值。我也使用PlayFramework,并在每次刷新时添加2个带属性的顶点(名称:Jan,name; Adam)。从图形嵌入式数据库中读取数据看起来很麻烦。有没有人有类似的麻烦?我正在附上调试列表,以向您展示我的问题的更好视角。 每个回复都要提前感谢;)

[debug] application - -----------------------------------------------
[debug] application - v[1] name: Adam Kowalski
[debug] application - v[2] name: Jan Nowak
[debug] application - -----------------------------------------------
[debug] application - v[1] name: Adam Kowalski
[debug] application - v[2] name: Jan Nowak
[debug] application - v[3] name: Adam Kowalski
[debug] application - v[4] name: Jan Nowak
[debug] application - -----------------------------------------------
[debug] application - v[1] name: null
[debug] application - v[2] name: null
[debug] application - v[3] name: null
[debug] application - v[4] name: null
[debug] application - v[5] name: Adam Kowalski
[debug] application - v[6] name: Jan Nowak
[debug] application - -----------------------------------------------
[debug] application - v[1] name: null
[debug] application - v[2] name: null
[debug] application - v[3] name: null
[debug] application - v[4] name: null
[debug] application - v[5] name: null
[debug] application - v[6] name: null
[debug] application - v[7] name: Adam Kowalski
[debug] application - v[8] name: Jan Nowak
[debug] application - -----------------------------------------------
[debug] application - v[1] name: null
[debug] application - v[2] name: null
[debug] application - v[3] name: null
[debug] application - v[4] name: null
[debug] application - v[5] name: null
[debug] application - v[6] name: null
[debug] application - v[7] name: Adam Kowalski
[debug] application - v[8] name: Jan Nowak
[debug] application - v[9] name: Adam Kowalski
[debug] application - v[10] name: Jan Nowak
[debug] application - -----------------------------------------------
[debug] application - v[1] name: null
[debug] application - v[2] name: null
[debug] application - v[3] name: null
[debug] application - v[4] name: null
[debug] application - v[5] name: null
[debug] application - v[6] name: null
[debug] application - v[7] name: Adam Kowalski
[debug] application - v[8] name: Jan Nowak
[debug] application - v[9] name: Adam Kowalski
[debug] application - v[10] name: Jan Nowak
[debug] application - v[11] name: Adam Kowalski
[debug] application - v[12] name: Jan Nowak
[debug] application - -----------------------------------------------
[debug] application - v[1] name: null
[debug] application - v[2] name: null
[debug] application - v[3] name: null
[debug] application - v[4] name: null
[debug] application - v[5] name: Adam Kowalski
[debug] application - v[6] name: Jan Nowak
[debug] application - v[7] name: null
[debug] application - v[8] name: null
[debug] application - v[9] name: null
[debug] application - v[10] name: null
[debug] application - v[11] name: null
[debug] application - v[12] name: null
[debug] application - v[13] name: Adam Kowalski
[debug] application - v[14] name: Jan Nowak
[debug] application - -----------------------------------------------
[debug] application - v[1] name: null
[debug] application - v[2] name: null
[debug] application - v[3] name: null
[debug] application - v[4] name: null
[debug] application - v[5] name: null
[debug] application - v[6] name: null
[debug] application - v[7] name: Adam Kowalski
[debug] application - v[8] name: Jan Nowak
[debug] application - v[9] name: Adam Kowalski
[debug] application - v[10] name: Jan Nowak
[debug] application - v[11] name: Adam Kowalski
[debug] application - v[12] name: Jan Nowak
[debug] application - v[13] name: null
[debug] application - v[14] name: null
[debug] application - v[15] name: Adam Kowalski
[debug] application - v[16] name: Jan Nowak

0 个答案:

没有答案