我有一个字符串,
"
it is a dog"
如何删除起始空白和新行? 输出应为:
"it is a dog"
我尝试了preg_replace("/^\s*/ms", "", $string)
,但没有效果。
答案 0 :(得分:2)
尝试ltrim (http://php.net/ltrim)。
答案 1 :(得分:2)
使用trim。
来自php.net的示例:
$text = "\t\tThese are a few words :) ... ";
$binary = "\x09Example string\x0A";
$hello = "Hello World";
var_dump($text, $binary, $hello);
print "\n";
$trimmed = trim($text);
var_dump($trimmed);
$trimmed = trim($text, " \t.");
var_dump($trimmed);
$trimmed = trim($hello, "Hdle");
var_dump($trimmed);
$trimmed = trim($hello, 'HdWr');
var_dump($trimmed);
// trim the ASCII control characters at the beginning and end of $binary
// (from 0 to 31 inclusive)
$clean = trim($binary, "\x00..\x1F");
var_dump($clean);
以上示例将输出:
string(32) " These are a few words :) ... "
string(16) " Example string
"
string(11) "Hello World"
string(28) "These are a few words :) ..."
string(24) "These are a few words :)"
string(5) "o Wor"
string(9) "ello Worl"
string(14) "Example string"
答案 2 :(得分:0)
你可以试试这个:
$string = str_replace(array("\r", "\n"), '', trim($string));