如何将文件输入到C ++并比较控制台输入

时间:2012-09-07 18:48:09

标签: c++ file input fstream

我正在完成我的家庭作业,因为在作业中我们必须要求用户输入文件名,而且还要键入wc cc或lc(字数,字符数和文件的行数)例如,wc filename.txt。我想检查文件,看看它是否有效,我知道如何比较用户输入,以确定运行的不同类型的功能,但我不明白你是怎么做的可以一起做。有什么想法吗?这就是我到目前为止所做的。

#include <iostream>
#include <string>
#include <fstream>

using namespace std;

int main()
{
string line;
string file;

ifstream input; //input file stream
int i;

cout << "Enter a file name" << endl;

while(true){

    cout << ">" ;
    getline(cin,file);

    input.open(file.c_str());

     if (input.fail()) {
        cerr << "ERROR: Failed to open file " << file << endl;
        input.clear();
     }
     else {
        i = 0;
        while (getline(input, line))

            if(line == "wc"){

            cout << "The word count is: " << endl;
    }
        else if(line == "cc"){

            cout << "The character count is: " << endl;
    }
        else if(line == "lc"){

            cout << "The line count is: " << endl;
    }
        else if(line == "exit"){

            return 0;
    }
        else{

            cout << "----NOTE----" << endl;
            cout << "Available Commands: " << endl;
            cout <<"lc \"filename\"" << endl;
            cout <<"cc \"filename\"" << endl;
            cout <<"wc \"filename\"" << endl;
            cout <<"exit" << endl;
    }



     }



}


return 0;
}

void wordCount(){
   //TBD
}

void characterCount(){
    //TBD

}

void lineCount(){
  //TBD

}

2 个答案:

答案 0 :(得分:0)

您必须在用户输入中找到命令和文件名之间的空格,然后将字符串拆分到找到空格的位置。像这样的东西

cout << "Enter a command\n";
string line;
getline(cin, line);
// get the position of the space as an index
size_t space_pos = line.find(' ');
if (space_pos == string::npos)
{
   // user didn't enter a space, so error message and exit
   cout << "illegal command\n";
   exit(1);
}
// split the string at the first space
string cmd = line.substr(0, space_pos);
string file_name = line.substr(space_pos + 1);

这是未经测试的代码。

你可以做得比这更好,例如,如果用户在命令和文件名之间输入两个空格,这将不起作用。但这种工作很快变得非常繁琐。由于这是一项任务,我很想转向更有趣的事情。如果你有时间,你可以随时回来改善事情。

答案 1 :(得分:0)

我想你问的是如何验证多个参数:命令和文件。

一个简单的策略是具有如下功能:

#include <fstream> // Note: this is for ifstream below

bool argumentsInvalid(const string& command, const string & command) {
    // Validate the command
    // Note: Not ideal, just being short for demo
    if("wc" != command && "cc" != command && "lc" != command) {
        std::cout << "Invalid command" << std::endl;
        return false;
    }

    // Validate the file
    // Note: This is a cheat that uses the fact that if its valid, its open.
    std::ifstream fileToRead(filename);
    if(!fileToRead) {
        std::cout << "Invalid file: \"" << filename << "\"" << std::endl;
        return false;
    }

    return true;
    // Note: This does rely on the ifstream destructor closing the file and would mean
    // opening the file twice.  Simple to show here, but not ideal real code.
}

如果要在返回错误之前评估所有参数,请在该函数的顶部插入一个标志,如:

// To be set true if there is an error
bool errorFound = false;

并将条件中的所有返回值更改为:

errorFound = true;

并最终返回:

return !errorFound;

用法:

....

if(argumentsInvalid(command, filename)) {
    std::cout << "Could not perform command.  Skipping..." << std::endl;
    // exit or continue or whatever
}

// Now do your work

注意:此处的特定有效性测试已经过度简化。