Question

我有以下SQl声明：

SELECT id  + 100000000000000000 AS id,  
    a.external_code + CAST(id AS varchar(15)) as crUniqueId,  
    m.check_amount,  
    'C' as crType,  
    m.postprint_date as activationDate,  
    m.postprint_date as creationDate,  
    m.memo_explanation as reasonLine1,  
    m.check_no, 
    m.check_amount - sh.sumAmount As dispositionAmount 
    FROM md_master m 
    Join accounts a on m.account_tag = a.acct_id 
    LEFT JOIN (SELECT master_id,  
                SUM(md_cr_pending.current_amount) as sumAmount  
                FROM md_cr_pending 
                Group BY master_id) sh ON master_id = m.ID 
    WHERE (m.postprint_tag = 2) OR (m.postprint_tag = 4) OR  
          (m.postprint_tag = 5) OR (m.postprint_tag = 7) 

    UNION ALL  

    SELECT id + 200000000000000000 as id,  
    'PERCHK' + CAST(id AS varchar(15)) as crUniqueId,  
    check_amount,  
    'P' as crType,  
    business_date as activationDate,  
    business_date as creationDate,  
    identify_description as reasonLine1,  
    check_no, 
    check_amount - sh.sumAmount As dispositionAmount 
    FROM cd_personal_checks  
    LEFT JOIN (SELECT cd_personal_checks_id,  
                SUM(md_cr_pending.current_amount) as sumAmount  
                FROM md_cr_pending 
                Group BY  cd_personal_checks_id) sh  
                ON sh.cd_personal_checks_id = cd_personal_checks.ID

我想为UNION的每个select语句添加一个额外的列。但是，我需要使用创建为前一列的别名。

例如。我想做以下

m.check_amount - sh.sumAmount As dispositionAmount, m.check_amount-dispositionAmount AS openBalance

和

check_amount - sh.sumAmount As dispositionAmount,  check_amount-dispositionAmount AS openBalance

分别

可以这样做吗？目前，我在上面的方式，我得到一个“无效的列名'dispositionAmount'”

感谢名单

Answer 1

不能它不能在同一级别上，因为您在“按顺序”部分中仅选择“可用”中的别名。这是因为逻辑查询处理。

为此你应该建立更多关卡，或者再次使用表达式。

我不知道，你想这样做：

m.check_amount - sh.sumAmount As dispositionAmount, 
m.check_amount - dispositionAmount AS openBalance

因为它等于：

m.check_amount - sh.sumAmount As dispositionAmount, 
m.check_amount - m.check_amount + sh.sumAmountAS AS openBalance

这是：

m.check_amount - sh.sumAmount As dispositionAmount, 
sh.sumAmountAS AS openBalance

Answer 2

不，它无法完成。您需要重复计算dispositonAmount。

...
m.check_amount - sh.sumAmount As dispositionAmount, 
m.check_amount - (m.check_amount - sh.sumAmount) AS openBalance
...

Answer 3

表达式check_amount-dispositionAmount与check_amount-(check_amount - sh.sumAmount)相同，与(check_amount-check_amount) + sh.sumAmount相同，因此只有sh.sumAmount。

所以：

check_amount - sh.sumAmount As dispositionAmount, sh.sumAmount AS openBalance

Answer 4

您可以使用CROSS APPLY CROSS APPLY

SELECT my_num, my_num*5 AS another_number FROM table CROSS APPLY (SELECT 5 AS my_num) X

在计算中使用SQL别名来创建其他别名

4 个答案: