Question

我使用d3js创建树形布局图。可以单击节点以切换显示子节点。应将子节点插入预定义位置，然后转换到所需位置。问题是插入坐标总是关闭。使用Firebug进行调试时，它会在附加新节点后直接显示其坐标为x = 51.42857142857142且y = 200.0，即使该行为 .attr("transform", "translate(90,100)" )应该改变它们（我在这里使用固定值，以进一步确定问题。

我的错误在哪里？

完整代码：

// Toggle children.
function toggle(d) {
   if (d.children) {
     d._children = d.children;
     d.children = null;
   } else {
     d.children = d._children;
     d._children = null;
  }
} 

function toggleAll(d) {
   if (d.children) {
      d.children.forEach(toggleAll);
      toggle(d);
   }
}

function update(source) {
   // Node movement delay
   var duration = d3.event && 1500;

   // Compute the new tree layout.
   var nodes = tree.nodes(root).reverse();

   // Normalize for fixed-depth.
   nodes.forEach(function(d) { d.y = d.depth * 100; });

   // Update the nodes…
   var node = vis.selectAll("g.node")
     .data(nodes, function(d) { return d.id || (d.id = ++i); });

  // Enter any new nodes at the parent's previous position.
   var nodeEnter = node.enter().append("svg:g")
    .attr("class", "node")
    .attr("transform", "translate(90,100)" )
    .on("click", function(d) { toggle(d); update(d); });

  nodeEnter.append("svg:circle")
    .attr("r", 1e-6);


  // Transition nodes to their new position.
  var nodeUpdate = node.transition()
    .duration(duration)
    .attr("transform", function(d) { return "rotate(" + (d.x - 90) + ")translate(" + d.y + ")"; })

  nodeUpdate.select("circle")
    .attr("r", 4.5)
    .style("fill", function(d) { return d._children ? "red" : "#fff"; });



  // Transition exiting nodes to the parent's new position.
  var nodeExit = node.exit().transition()
     .duration(duration)
     .attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
    .remove();

 // While moving the nodes, they need to shrink
 nodeExit.select("circle")
   .attr("r", 1e-6);


    // Stash the old positions for transition.
    nodes.forEach(function(d) {
    d.x0 = d.x;
    d.y0 = d.y;
   });
}


var i = 0, root;
var radius = 960 / 2;
var tree = d3.layout.tree()
   .size([360, radius - 120]);
var diagonal = d3.svg.diagonal.radial()
   .projection(function(d) { return [d.y, d.x / 180 * Math.PI]; });

var vis = d3.select("#body").append("svg:svg")
   .attr("width", radius * 2)
   .attr("height", radius * 2 - 50)
   .append("g")
   .attr("transform", "translate(" + radius + "," + radius + ")");

d3.json("flare.json", function(json) {
  root = json;
  root.x0 = 0;
  root.y0 = 0;


  // Initialize the display to show a few nodes.
  root.children.forEach(toggleAll);
  toggle(root.children[1]);

  update(root);
});

Answer 1

您可以通过调整初始transform来更改插入坐标，即更改

.attr("transform", "translate(90,100)")

例如，如果要在父节点的位置插入新节点，可以通过将对父元素的引用传递给update函数并获取其transform来实现此目的。值：

var sourceNode = d3.select(parentElement);

// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("svg:g")
    .attr("class", "node")
    .attr("transform", parentElement ? sourceNode.attr("transform") : "translate(90,100)")
    .on("click", function (d) {
    toggle(d);
    update(d, this);
});

完成jsfiddle here。

d3.tree =＆gt;变换似乎不起作用

1 个答案: