Question

我是第一次在Django中创建一个Python应用程序。我知道我必须取消注释urls.py中的管理工具，我已经这样做了。我还添加了autodiscover。每次我尝试向管理面板添加新功能时，都会收到此错误：

“NameError：名称'admin'未定义”

以下是我在模型中使用的代码，用于添加到管理面板：

class ChoiceInline(admin.StackedInline):
    model = Choice
    extra = 3

    class PollAdmin(admin.ModelAdmin):
    fieldsets = [
        (None,               {'fields': ['question']}),
        ('Date information', {'fields': ['pub_date'], 'classes': ['collapse']}),
    ]
    inlines = [ChoiceInline]

这是我正在使用的python终端中的代码

admin.site.register(Poll, PollAdmin)

这是我的urls.py中的代码：

from django.conf.urls import patterns, include, url

# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'iFriends.views.home', name='home'),
    # url(r'^iFriends/', include('iFriends.foo.urls')),

    # Uncomment the admin/doc line below to enable admin documentation:
    # url(r'^admin/doc/', include('django.contrib.admindocs.urls')),

    # Uncomment the next line to enable the admin:
    url(r'^admin/', include(admin.site.urls)),
    )

任何人都知道为什么找不到管理员名称？

修改

这是我的整个模型文件：

from django.db import models

class Poll(models.Model):
    question = models.CharField(max_length=200)
    pub_date = models.DateTimeField('date published')
    def __unicode__(self):
        return self.question
    def was_published_recently(self):
        return self.pub_date >= timezone.now() - datetime.timedelta(days=1)

    class Choice(models.Model):
    poll = models.ForeignKey(Poll)
    choice_text = models.CharField(max_length=200)
    votes = models.IntegerField()
    def __unicode__(self):
        return self.choice_text


#COMMENTED OUT UNTIL I FIX THE ADMIN NAME
from django.config import admin

class ChoiceInline(admin.StackedInline):
    model = Choice
    extra = 3

    class PollAdmin(admin.ModelAdmin):
    fieldsets = [
        (None,               {'fields': ['question']}),
        ('Date information', {'fields': ['pub_date'], 'classes': ['collapse']}),
    ]
    inlines = [ChoiceInline]

#ADD THIS TO THE MAIN PYTHON FUNCTION
admin.site.register(Poll, PollAdmin)

Answer 1

from django.config import admin应为from django.contrib import admin

Answer 2

在**url.py**文件的顶部，添加以下代码

from django.contrib import admin
admin.autodiscover()

因此，特定块应该类似于以下

from django.conf.urls import patterns, include, url
**from django.contrib import admin
admin.autodiscover()**

# Uncomment the next two lines to enable the admin:
# from django.contrib import admin
# admin.autodiscover()

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'examplesite.views.home', name='home'),
    # url(r'^examplesite/', include('examplesite.foo.urls')),

    # Uncomment the admin/doc line below to enable admin documentation:
    #url(r'^admin/doc/', include('django.contrib.admindocs.urls')),

    # Uncomment the next line to enable the admin:
**url(r'^admin/', include(admin.site.urls)),**

)

Answer 3

经过漫长而痛苦的追求来解决这个愚蠢的问题之后，我终于找到了答案！另一个Django程序员遇到了同样的问题，发现了这个：

在ChoiceInLine的父母（你在教程中你会看到'admin.StackedInline'）中，堆叠的内联不应该被资本化......它就像那样简单......比Karen Tracey多得多。 ..

http://grokbase.com/p/gg/django-users/133v4wx0sx/django-1-5-tutorial-error-module-has-no-attribute-stackedinline

Answer 4

我这样更改了我的urls.py ......这应该是基本格式

from django.conf.urls import  include, url
from django.contrib import admin

admin.autodiscover()
urlpatterns = [
     url(r'^admin/', include(admin.site.urls)),
    ]

Answer 5

我怀疑您的模型文件中没有from django.contrib import admin，您定义了ModelAdmin个类class ChoiceInline(admin.StackedInline):。

Answer 6

您应该将管理代码（#COMMENTED OUT之后的所有内容直到我修复管理员名称）放到admin.py

Answer 7

为我解决此问题的一种方法是将其添加到admin.py的开头：

from django.contrib import admin

Python错误：未定义名称“admin”

7 个答案: