Question

可能重复：
Cannot use call_user_func_array on mysqli_stmt object

我有一段mysqli代码，它在这行代码中输出警告：

if (!$stmt = $mysqli->prepare($questionquery)) {
  die("Error preparing statement: $mysqli->error"); 
}

警告是：

Warning: Wrong parameter count for mysqli_stmt::bind_param() in ... line 80

以下是主要代码：

// Make the referenced array
$referencedArray = make_values_referenced(array_merge(
  array(str_repeat("ss", $numTerms)), // types
  $termArray,                         // where
  $termArray                          // order by
));

// ...or die() is evil in production but I shall assume we are debuggin so I won't complain
if (!$stmt = $mysqli->prepare($questionquery)) {
  die("Error preparing statement: $mysqli->error"); 
}

// Bind parameters
if (!$stmt->bind_param($referencedArray)) {
  die("Error binding parameters: $stmt->error"); 
}

Answer 1

您可以直接调用该方法：

$stmt->bind_param($referencedArray);

编辑：其实我错了。对于可变数量的参数，您需要call_user_func_array。请参阅此答案以获取解决方案：https://stackoverflow.com/a/5108167/163024

绑定参数导致警告

1 个答案: