我想在我的联系表格上提供*全名,*电子邮件地址和*主题和*消息。我按照教程开发了我的表单但由于某种原因它没有发送我的测试信息。
我对PHP没有足够的经验来弄清楚我做错了什么,所以我希望得到关于如何解决这个问题的建议。欢迎提出所有问题,建议和可能的解决方案。感谢。
联系表格php: 代码:
<?php
// EDIT THE FOLLOWING LINE BELOW AS REQUIRED
$send_email_to = "jb@me.com";
function send_email($name,$email,$email_subject,$email_message)
{
global $send_email_to;
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= "From: ".$email. "\r\n";
$message = "<strong>Email = </strong>".$email."<br>";
$message .= "<strong>Name = </strong>".$name."<br>";
$message .= "<strong>Message = </strong>".$email_message."<br>";
@mail($send_email_to, $email_subject, $message,$headers);
return true;
}
function validate($name,$email,$message,$subject)
{
$return_array = array();
$return_array['success'] = '1';
$return_array['name_msg'] = '';
$return_array['email_msg'] = '';
$return_array['message_msg'] = '';
$return_array['subject'] = '';
if($email == '')
{
$return_array['success'] = '0';
$return_array['email_msg'] = 'email is required';
}
else
{
$email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
if(!preg_match($email_exp,$email)) {
$return_array['success'] = '0';
$return_array['email_msg'] = 'enter valid email.';
}
}
if($name == '')
{
$return_array['success'] = '0';
$return_array['name_msg'] = 'name is required';
}
else
{
$string_exp = "/^[A-Za-z .'-]+$/";
if (!preg_match($string_exp, $name)) {
$return_array['success'] = '0';
$return_array['name_msg'] = 'enter valid name.';
}
}
if($subject == '')
{
$return_array['success'] = '0';
$return_array['subject_msg'] = 'subject is required';
}
if($message == '')
{
$return_array['success'] = '0';
$return_array['message_msg'] = 'message is required';
}
else
{
if (strlen($message) < 2) {
$return_array['success'] = '0';
$return_array['message_msg'] = 'enter valid message.';
}
}
return $return_array;
}
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$subject = $_POST['subject'];
$return_array = validate($name,$email,$message,$subject);
if($return_array['success'] == '1')
{
send_email($name,$email,$subject,$message);
}
header('Content-type: text/json');
echo json_encode($return_array);
die();
?>
联系表单HTML: 代码:
<fieldset id="contact_form">
<div id="msgs"> </div>
<form id="cform" name="cform" method="post" action="">
<input type="text" id="name" name="name" value="Full Name*" onfocus="if(this.value == 'Full Name*') this.value = ''"
onblur="if(this.value == '') this.value = 'Full Name*'" />
<input type="text" id="email" name="email" value="Email Address*" onfocus="if(this.value == 'Email Address*') this.value = ''"
onblur="if(this.value == '') this.value = 'Email Address*'" />
<input type="text" id="subject" name="subject" value="Subject*" onfocus="if(this.value == 'Subject*') this.value = ''"
onblur="if(this.value == '') this.value = 'Subject*'" />
<textarea id="msg" name="msg" onfocus="if(this.value == 'Your Message*') this.value = ''"
onblur="if(this.value == '') this.value = 'Your Message*'">Your Message*</textarea>
<button id="submit" class="button"> Send Message</button>
</form>
</fieldset>
答案 0 :(得分:0)
您的表单的操作未设置为任何内容。您需要将其指向您在那里发送电子邮件的脚本。
即:
<form id.. name.. method.. action="/handle_post.php">
答案 1 :(得分:0)
设置正确的操作,然后尝试它应该工作.. 如果它仍然不起作用测试它与curl实用程序,看看你的脚本是否正常.. 我看到的另一个错误是你的文本区域表单名称是msg,而在服务器上你期望你的帖子请求它有消息。那不行.. 如果你仍然面临问题,那么我们进一步调试:)
答案 2 :(得分:0)
首先,您需要将操作设置为某个脚本,该脚本将处理同一文件的$_POST
输入(contactform.php
)或$_SERVER['PHP_SELF']
。
其次,您应该按输入type=submit
而非按钮发送数据。