Question

我正在Android中创建一个HttpPost对象，以便与客户端运营的服务器进行通信。不幸的是，服务器没有向我们提供非常有用的错误消息;我希望将HttpPost对象的内容视为字符串，以便将其发送给我们的客户，并将其与他期望的内容进行比较。

如何将HttpPost对象转换为反映当它到达服务器时的外观的字符串？

Answer 1

我通常以这种方式发帖（服务器答案是JSON对象）：

    try {
        postJSON.put("param1", param1);
        postJSON.put("param2",param2);

    } catch (JSONException e) {
        e.printStackTrace();
    }

    String result = JSONGetHTTP.postData(url);
    if (result != null) {
        try {

            JSONObject jObjec = new JSONObject(result);

            }
        } catch (JSONException e) {
            Log.e(TAG, "Error setting data " + e.toString());
        }
    }

postData是：

public static String postData(String url, JSONObject obj) {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = null;
    try {
        HttpParams myParams = new BasicHttpParams();
        HttpConnectionParams.setConnectionTimeout(myParams, 30000);
        HttpConnectionParams.setSoTimeout(myParams, 30000);
        httpclient = new DefaultHttpClient(myParams);

    } catch (Exception e) {
        Log.e("POST_DATA", "error in httpConnection");
        e.printStackTrace();
    }

    InputStream is = null;
    try {
        HttpPost httppost = new HttpPost(url.toString());
        //Header here   httppost.setHeader();
        StringEntity se = new StringEntity(obj.toString());

        httppost.setEntity(se);

        HttpResponse response = httpclient.execute(httppost);

        HttpEntity entity = response.getEntity();
        // // Do something with response...
        is = entity.getContent();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    // convert response to string
    BufferedReader reader = null;
    String result = null;
    try {
        reader = new BufferedReader(new InputStreamReader(is, "UTF-8"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }

        result = sb.toString();

    } catch (Exception e) {
        Log.e("log_tag", "Error converting result " + e.toString());
    } finally {

        try {
            if (reader != null)
                reader.close();
            if (is != null)
                is.close();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }

    if (result != null) {
        try {
            @SuppressWarnings("unused")
            JSONObject jObjec = new JSONObject(result);

        } catch (JSONException e) {
            Log.e("log_tag", "Error parsing data " + e.toString());
        }
    }

    return result;
}

希望有所帮助

Answer 2

我确实HTTP-Post使用NameValuePair ......我正在显示用于执行HTTP-Post然后转换响应的代码进入String

请参阅以下方法代码：

public String postData(String url, String xmlQuery) {



final String urlStr = url;
final String xmlStr = xmlQuery;
final StringBuilder sb  = new StringBuilder();


Thread t1 = new Thread(new Runnable() {

public void run() {

    HttpClient httpclient = new DefaultHttpClient();

    HttpPost httppost = new HttpPost(urlStr);


    try {

         List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);

         nameValuePairs.add(new BasicNameValuePair("xml", xmlStr));

         httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

         HttpResponse response = httpclient.execute(httppost);

         Log.d("Vivek", response.toString());

        HttpEntity entity = response.getEntity();
        InputStream i = entity.getContent();

        Log.d("Vivek", i.toString());
        InputStreamReader isr = new InputStreamReader(i);

        BufferedReader br = new BufferedReader(isr);

        String s = null;


        while ((s = br.readLine()) != null) {

            Log.d("YumZing", s);
            sb.append(s);
        }


        Log.d("Check Now",sb+"");




        } catch (ClientProtocolException e) {

                e.printStackTrace();

                } catch (IOException e) {

                    e.printStackTrace();
                } 
            }

        });

        t1.start();
        try {
            t1.join();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }


        System.out.println("Getting from Post Data Method "+sb.toString());

        return sb.toString();
    }

Answer 3

执行后应该使用它

public static String httpPostToString(HttpPost httppost) {
    StringBuilder sb = new StringBuilder();
    sb.append("\nRequestLine:");
    sb.append(httppost.getRequestLine().toString());

    int i = 0;
    for(Header header : httppost.getAllHeaders()){
      if(i == 0){
          sb.append("\nHeader:");
      }
        i++;
        for(HeaderElement element : header.getElements()){
            for(NameValuePair nvp :element.getParameters()){
                sb.append(nvp.getName());
                sb.append("=");
                sb.append(nvp.getValue());
                sb.append(";");
            }
        }
    }
    HttpEntity entity = httppost.getEntity();

    String content = "";
    if(entity != null){
        try {

            content = IOUtils.toString(entity.getContent());
        } catch (Exception e) {
            e.printStackTrace();
        } 
    }
    sb.append("\nContent:");
    sb.append(content);


    return sb.toString();
}

snippet

如何将Java HttpPost对象显示为字符串？

3 个答案: