Question

我有一个List<Dictionary<string,string>>对象（每个列表对象中的Dict中的键是相同的），我想将它转换为List<object>，可以手动绑定到Datagrid生成列。这将使原始列表对象中的每个Dictionary<string,string>成为数据网格中的一行，而预期要绑定的对象上的属性是字典中的键。

非常感谢，

卫

Answer 1

执行类似

的操作

   <ListView Name="selectedPeople"
                  Width="480"
                  Height="200"
                  HorizontalAlignment="Right"
                  VerticalAlignment="Top"
                  ItemsSource="{Binding Path=Maps,
                                        RelativeSource={RelativeSource AncestorType=Window},
                                        Mode=OneWay}">
            <ListView.View>
                <GridView AllowsColumnReorder="True" ColumnHeaderToolTip="Broadcast call targets">
                    <GridViewColumn DisplayMemberBinding="{Binding Path=Key}" Header="ID" />
                    <GridViewColumn DisplayMemberBinding="{Binding Path=Value}" Header="Description" />
                    <GridViewColumn Header="">
                        <GridViewColumn.CellTemplate>
                            <DataTemplate>
                                <Button Content=" X " IsEnabled="{Binding RelativeSource={RelativeSource AncestorType={x:Type ListViewItem}}, Path=IsSelected}" />
                            </DataTemplate>
                        </GridViewColumn.CellTemplate>
                    </GridViewColumn>
                </GridView>
            </ListView.View>
        </ListView>





  public partial class Listviewsamples : Window
    {
        public Listviewsamples()
        {
            InitializeComponent();

            Maps = new ObservableCollection<Dictionary<string, string>>();

            for (int i = 0; i < 10; i++)
            {
                Dictionary<string, string> item = new Dictionary<string, string>();
                item.Add(i.ToString(), " Item " + i.ToString());
                Maps.Add(item);
            }
            this.DataContext = this;
        }
        public ObservableCollection<Dictionary<string, string>> Maps { get; set; }


    }

Answer 2

我认为最简单的方法是创建一个表并将其填充为：我们假设名为lst

的列表

DataTable table = new DataTable();

foreach (var col in lst[0].Keys)
{
     table.Columns.Add(col, typeof(string));
}

foreach (var dict in lst)
{
     var row = table.NewRow();

     foreach (var data in dic)
     {
         row[data.Key] = data.Value;
     }

     table.Rows.Add(row);
}

现在要做的就是将该表绑定到DataGrid！

如何转换List <dictionary <string，string>＆gt;对象到List <object>绑定到Datagrid？</object> </dictionary <string，string>

2 个答案: