Question

我正在使用此代码查找位置的纬度

$api='http://maps.googleapis.com/maps/api/geocode/json?address=United States Neversink&sensor=false';

$result = file_get_contents($api);

$data = json_decode($result);

但它会发出警告警告：file_get_contents（http://maps.googleapis.com/maps/api/geocode/json?address=United States Neversink＆amp; sensor = false）[function.file-get-contents]：无法打开流：HTTP请求失败！第139行的C：\ wamp \ www \ new_yellowpages \ modules \ mod_yellowpages_item_map \ helper.php中的HTTP / 1.0 400错误请求

如果有人知道这个问题请帮助我。

Answer 1

使用curl代替file_get_contents：

$address = "India+Panchkula";
$url = "http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false&region=India";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_PROXYPORT, 3128);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
$response = curl_exec($ch);
curl_close($ch);
$response_a = json_decode($response);
echo $lat = $response_a->results[0]->geometry->location->lat;
echo "<br />";
echo $long = $response_a->results[0]->geometry->location->lng;

Answer 2

使用urlencode对地址部分进行编码。（问题是地址中的空格。）

$address = urlencode("United States Neversink");
$api='http://maps.googleapis.com/maps/api/geocode/json?address=$address&sensor=false';

$result = file_get_contents($api);

Answer 3

使用urlenocde函数对您的地址进行编码（如Google Map Standard），然后将Http更改为https。希望这对您有用

Answer 4

尝试将HTTP更改为HTTPS并将''替换为'+'

https://maps.googleapis.com/maps/api/geocode/json?address=United+States+Neversink&sensor=false

Answer 5

使用curl_init（）代替file_get_contents（）：

$address = "India+Panchkula";
$url = "http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false&region=India";

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_PROXYPORT, 3128);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
$response = curl_exec($ch);
curl_close($ch);

$response_a = json_decode($response);
echo $lat = $response_a->results[0]->geometry->location->lat;
echo "<br />";
echo $long = $response_a->results[0]->geometry->location->lng;

使用google api的file_get_contents时出现警告

5 个答案: