Question

如何在意图中获得微调器的选定位置并将其作为参数传递给另一个Activity？

 spinner  sp;
if (position==1) {
 do this
} if (position==2) {
 do this
}

Intent i = new Intent(this.getApplicationContext(), AgAppMenu.class);
Bundle bundle = new Bundle();
bundle.putString("mno", mobile.getText().toString());
bundle.putString("pinno", pin.getText().toString());
bundle.putLong("CODE",sp.getSelectedItemPosition());

Answer 1

也许这就是你想要做的事情？

sp.setOnItemSelectedListener(new OnItemSelectedListener() {
            @Override
            public void onItemSelected(AdapterView<?> av, View v,
                    int pos, long id) {
                //do something with the pos var
            }
            @Override
            public void onNothingSelected(AdapterView<?> arg0) {}                       
        });

Answer 2

如果我理解正确的话。现在你所缺少的是

intent.putExtras(bundle);
startActivity(intent);

编辑：

要获取该值，请使用

(YourType) sp.getSelectedItem();

其中YourType是您希望获得的值的类型。如果是Long，请将其投放到Long。

Answer 3

定义一个类变量（此处为String selectedMonth）并在以下方法中为其赋值，然后在intent中使用此变量

public void onItemSelected（AdapterView month，View arg1，int arg2，long arg3）{

    selectedMonth=  month.getItemAtPosition(arg2).toString();

        }

Answer 4

String item;
sp.setOnItemSelectedListener(new OnItemSelectedListener() {
public void onItemSelected(AdapterView<?> arg0, View arg1,int arg2, long arg3) {
item = (String) arg0.getItemAtPosition(arg2);
}
public void onNothingSelected(AdapterView<?> arg0) {
// TODO Auto-generated method stub
}
});

Intent i = new Intent(this.getApplicationContext(), AgAppMenu.class);
Bundle bundle = new Bundle(); bundle.putString("CODE",item);

如何在意图中获得选定的微调器值？

4 个答案: