Android:如何以编程方式创建GridLayout [不是GridView]?

时间:2012-09-05 11:29:45

标签: android android-layout grid-layout

我正在开发一个“匹配以下”应用程序。用于该应用程序的xml如下:

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/lytLinear"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <TextView
        android:id="@+id/txtQuestion"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:paddingBottom="30dp"
        android:text="Match the following questions with their answers." />

    <GridLayout
        android:id="@+id/lytGrid"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:columnCount="3"
        android:columnWidth="300dp"
        android:orientation="vertical"
        android:rowCount="5"
        android:stretchMode="columnWidth" >

        <LinearLayout
            android:id="@+id/Q1Lyt"
            android:layout_width="160dp"
            android:layout_height="50dp"
            android:layout_column="0"
            android:layout_row="0"
            android:background="@drawable/shape_qn"
            android:gravity="center" >

            <TextView
                android:id="@+id/Q1"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:layout_column="0"
                android:layout_row="0"
                android:text="Question1" />
        </LinearLayout>

        <LinearLayout
            android:id="@+id/A1Lyt"
            android:layout_width="160dp"
            android:layout_height="50dp"
            android:layout_column="1"
            android:layout_row="0"
            android:background="@drawable/shape"
            android:gravity="center"
            android:text="Answer1" >

            <TextView
                android:id="@+id/A1"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:layout_column="0"
                android:layout_row="0"
                android:text="Answer1" />
        </LinearLayout>

        <LinearLayout
            android:id="@+id/Q2Lyt"
            android:layout_width="160dp"
            android:layout_height="50dp"
            android:layout_column="0"
            android:layout_row="1"
            android:background="@drawable/shape_qn"
            android:gravity="center" >

            <TextView
                android:id="@+id/Q2"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:text="Question2" />
        </LinearLayout>

        <LinearLayout
            android:id="@+id/A2Lyt"
            android:layout_width="160dp"
            android:layout_height="50dp"
            android:layout_column="1"
            android:layout_row="1"
            android:background="@drawable/shape"
            android:gravity="center" >

            <TextView
                android:id="@+id/A2"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:layout_column="0"
                android:layout_row="0"
                android:text="Answer2" />
        </LinearLayout>
   </GridLayout>
 </LinearLayout>

我尝试了以下代码来创建网格布局。但是,对于子线性布局,我无法找到以编程方式设置android:layout_column和android:layout_row参数的方法。

GridLayout gridLayout = new GridLayout(this);
    gridLayout.setColumnCount(2);
    gridLayout.setRowCount(15);

    LinearLayout lyt1 = new LinearLayout(this);
    LinearLayout.LayoutParams prmsLinLyt = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT, LinearLayout.LayoutParams.WRAP_CONTENT);

任何指针?

2 个答案:

答案 0 :(得分:7)

以下是您可以通过编程方式创建它的方法:

GridLayout gridLayout = new GridLayout(getContext());

// Add Title
GridLayout.Spec titleTxtSpecColumn = GridLayout.spec(2, GridLayout.BASELINE);
GridLayout.Spec titleRowSpec = GridLayout.spec(0);
TextView titleText = new TextView(getContext());
titleText.setText("Title");

gridLayout.addView(titleText, new GridLayout.LayoutParams(titleRowSpec , titleTxtSpecColumn));

有关详细信息,请参阅ApiDemos示例。

答案 1 :(得分:-3)

你应该试试这个:

  gridLayout.setLayoutParams(prmsLinLyt);

如果你想给价值......

LinearLayout.LayoutParams prmsLinLyt = new LinearLayout.LayoutParams(90,100);

where layout_width = 90
and layout_height= 100