Question

我们有2个非常简单的SELECT语句：

SELECT value from table where date between DATE1 and DATE2
SELECT value from table where date between DATE3 and DATE4

我们需要一种方法来编写单个SQL语句，它将获得从这两个SQL语句返回的“值”的差异。

我们尝试了以下但是没有成功：

SELECT value from table where date between DATE1 and DATE2
minus 
SELECT value from table where date between DATE3 and DATE4

任何建议都非常感谢。

Answer 1

未经测试但应该有效：

SELECT
    (SELECT value from table where date between DATE1 and DATE2) - 
    (SELECT value from table where date between DATE3 and DATE4)
FROM dual;

假设您的SELECT value保证返回单个值

Answer 2

SELECT value FROM TBL WHERE date BETWEEN DATE1 and DATE2 
AND value NOT IN (SELECT value FROM TBL WHERE date BETWEEN DATE3 AND DATE4)

Answer 3

如果您认为您的内部查询可以提供多个值，请使用下面的

SELECT
    (SELECT sum(value) from table where date between DATE1 and DATE2) - 
    (SELECT sum(value) from table where date between DATE3 and DATE4) as answer
FROM dual;

Answer 4

请试试这个：

SET SERVEROUTPUT ON
DECLARE
V_FIRST NUMBER := 0;
V_SECOND NUMBER := 0;
BEGIN
  SELECT value into V_FIRST from table where rownum=1 and date between DATE1 and DATE2;
  SELECT value into V_SECOND from table where rownum=1 and date between DATE3 and DATE4;

  DBMS_OUTPUT.PUT_LINE (V_FIRST-V_SECOND); 
END;

Answer 5

(
SELECT value from table where date between DATE1 and DATE2
 minus 
SELECT value from table where date between DATE3 and DATE4
)
union all
(
SELECT value from table where date between DATE3 and DATE4
 minus 
SELECT value from table where date between DATE1 and DATE2
)

Answer 6

以下声明适用于您的案例

(
SELECT value from table where date between DATE3 and DATE4
 minus 
SELECT value from table where date between DATE1 and DATE2
)
union
(
SELECT value from table where date between DATE1 and DATE2
 minus 
SELECT value from table where date between DATE3 and DATE4
)

ORACLE SQL从2个select语句中获取两个值的差异

6 个答案: