Question

我正在为图书馆系统做一个整理，并修复杂乱的书名。我想编写一个SQL查询或PHP代码，用于搜索与MySQL表中的数据匹配的关键字。

[tbl_keywords]

id | keyword             | title
====================================================================
 1 | Harry Potter        | Harry Potter
 2 | Philosopher's Stone | [Harry Potter] Harry Potter and the Philosopher's Stone
 3 | Chamber of Secrets  | [Harry Potter] Harry Potter and the Chamber of Secrets
 4 | Dr. Seuss           | Dr. Seuss
 5 | Green Eggs and Ham  | [Dr. Seuss] Green Eggs and Ham
 6 | The Cat in the Hat  | [Dr. Seuss] The Cat in the Hat

例如，

"Harry Potter(1)" => matches 1
"[Harry Potter] Harry Potter and the Philosopher's Stone(1)" => matches 1 and 2
"(HARRY POTTER2) THE CHAMBER OF SECRETS" => matches 1 and 3
"Dr. Seuss - Green Back Book" => matches 4
"Green eggs and ham" => matches 5
"the cat in the hat(Dr. Seuss)" => matches 4 and 6

这也可能（易于实施）？如果它太多了，我只需将变量值添加到表中..

"HarryPotter" => matches 1
"Dr.Seuss" => matches 4
"Dr Seuss" => matches 4

任何有关如何执行此操作的帮助或想法将不胜感激。提前谢谢。

Answer 1

在SQL where where条件中使用LIKE。

示例：

$input_search //your search input
$sql1 = 'Select * from `tbl_keywords` where keyword ="'.$input_search.'"';
//...the rest of code
$sql2 = 'Select * from `tbl_keywords` where keyword LIKE "%'.$input_search.'%" OR title LIKE "%'.$input_search.'%"';
//... the rest of code
//here is IF condition to get the desire result from the sql result you got

Answer 2

Jst写得像这样

$element_to_search='//get here the input to search';
$sql2 = 'Select * from `tbl_keywords` where keyword LIKE "%'.$element_to_search.'%" OR title LIKE "%'.$element_to_search.'%"';

在你的情况下，总是把要搜索的key_element放在两个“％HERE％”之间，因为

“HERE％”将导致其键以＆和

开头

“％HERE”将导致其键结束，

但如果你输入“％HERE％”，它将导致所有包含“key_element”的元素作为子字符串。谢谢

Answer 3

PHP stristr用于查找数组中的每个关键字，而不是SQL。

search in text , and select keywords by php

然后，在MySQL表中查找ID以获取其他信息/字段;标题，类别等。

$keywords = array(NULL, 'Harry Potter', 'Philosopher\'s Stone', 'Chamber of Secrets');
$input_title = "[Harry Potter] Harry Potter and the Philosopher\'s Stone(1)"

$keyword_found = array();
foreach ($keywords as $key => $val) {
    if (stristr($input_title, $val)) $keyword_found[] = $key;
}

if ($keyword_found) {
    foreach ($keyword_found as $val) {
        $sql = "SELECT * FROM `tbl_keywords` WHERE `id` = '" . $val . "'";
        ...
    }
}

它不整洁，必须有更好的方法，但......至少它有效！再次感谢那些试图帮助我的人：）

搜索与MySQL中的数据匹配的关键字

3 个答案: