为什么日期选择器不显示..我希望日期选择器以2形式显示,因为它有日期开始和日期结束.......... 谢谢你的帮助......
<script type="text/javascript" src="jquery.1.4.2.js"></script>
<script type="text/javascript" src="jsDatePick.jquery.min.1.3.js"></script>
<script type="text/javascript">
window.onload = function(){
new JsDatePick({
useMode:2,
target:"inputField",
dateFormat:"%d-%M-%Y"
});
};
</script>
<form action="index.php?page=form" method="post">
<table>
<tr>
<td>
Date Start
</td>
<td>
<input type="text" name="date1" id="inputField">
</td>
</tr>
<tr>
<td>
Date Finish
</td>
<td>
<input type="text" name="date2" id="inputField">
</td>
</tr>
</table>
答案 0 :(得分:0)
<script type="text/javascript" src="jquery.1.4.2.js"></script>
<script type="text/javascript" src="jsDatePick.jquery.min.1.3.js"></script>
<script type="text/javascript">
window.onload = function(){
new JsDatePick({
useMode:2,
target:"inputField",
dateFormat:"%d-%M-%Y"
});
new JsDatePick({
useMode:2,
target:"inputField2",
dateFormat:"%d-%M-%Y"
});
};
</script>
<form action="index.php?page=form" method="post">
<table>
<tr>
<td>
Date Start
</td>
<td>
<input type="text" name="date1" id="inputField">
</td>
</tr>
<tr>
<td>
Date Finish
</td>
<td>
<input type="text" name="date2" id="inputField2">
</td>
</tr>
</table>
答案 1 :(得分:0)
ID应该是唯一的,您应该为输入字段分配不同的ID。还要将代码包装在$(document).ready( function()
之内;
$(document).ready( function(){
new JsDatePick({
useMode:2,
target:"inputField",
dateFormat:"%d-%M-%Y"
});
new JsDatePick({
useMode:2,
target:"inputField2",
dateFormat:"%d-%M-%Y"
});
});
注意:我没有测试过这个。