Question

我有一个客户详细信息表，由ID标识，如下所示：

ID (the clientcode), Name, Details

我想从另一个包含销售信息的表中引用ID，并在查询中选择客户端的名称。

我只获取ID（客户端代码）的原始查询字符串是：

SELECT clientcode, SUM(sales) FROM inventory WHERE manufacturer='1' 
  GROUP BY client code ORDER BY SUM(sales) DESC

我还想选择客户端代码引用的客户端的名称。

我尝试了一些LEFT JOIN但无法使查询正常工作。

Answer 1

SELECT i.clientcode
     , c.name
     , SUM(i.sales)
  FROM inventory i
  LEFT
  JOIN clientdetails c
    ON c.id = i.clientcode
 WHERE i.manufacturer='1' 
 GROUP BY i.clientcode, c.name
 ORDER BY SUM(i.sales) DESC

Answer 2

这应该这样做

SELECT c.ID, c.name, SUM(i.sales) 
FROM inventory i
JOIN clients c ON c.ID = i.clientcode
WHERE i.manufacturer='1' 
GROUP BY c.ID, ORDER BY SUM(i.sales) DESC

Answer 3

实现这一目标的简单查询是：

SELECT i.clientcode, d.name, SUM(i.sales) FROM inventory i, details d
WHERE i.manufacturer='1'
  AND d.clientcode = i.clientcode
GROUP BY i.clientcode ORDER BY SUM(i.sales) DESC

Answer 4

在这里，试试这个。

SELECT  inventory.clientcode, 
        SUM(inventory.sales),
        clientdetails.Name
FROM inventory 
        INNER JOIN clientdetails
            ON inventory.clientcode = clientdetails.clientcode
WHERE inventory.manufacturer='1' 
GROUP BY inventory.clientcode, clientdetails.Name
ORDER BY SUM(inventory.sales) DESC

Answer 5

SELECT  a.clientcode, 
        SUM(a.sales),
        b.Name
FROM inventory a
        INNER JOIN clientdetails b
            ON a.clientcode = b.clientcode
WHERE a.manufacturer='1' 
GROUP BY a.clientcode, b.Name
ORDER BY SUM(a.sales) DESC

将一个MySQL表的ID名称加入另一个MySQL表中的ID

5 个答案: