我制作了一个脚本,用于检测是否存在互联网连接:
public static boolean isOnline() {
try {
InetAddress.getByName("google.hu").isReachable(3);
return true;
} catch (UnknownHostException e){
return false;
} catch (IOException e){
return false;
}
}
如果没有互联网,该应用程序将警告用户并退出!但是如何延迟super.onBackPressed 20秒呢? :)
this.toast1 = new Toast(getApplicationContext());
toast1.setGravity(Gravity.CENTER, 0, 0);
toast1.setDuration(20000);
toast1.setView(layout);
toast1.show();
super.onBackPressed();
答案 0 :(得分:1)
Thread delayThread= new Thread(new Runnable()
{
@Override
public void run()
{
try
{
Thread.sleep(1000);
}
catch (InterruptedException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
activityInstance.this.runOnUiThread(new Runnable()
{
@Override
public void run()
{
super.onBackPressed();
}
});
}
});
delayThread.start();
答案 1 :(得分:0)
最简单的方法是在Handler
中创建onCreate()
,并使用Runnable
与super.onBackPressed()
调用{{1}}