我一直在努力解决这个问题,并且会喜欢一些新鲜的想法。
我有一个包含重复活动的活动日历。当我尝试更新重复发生的事件时,我遇到了一些问题。
我有一个简单的表单,我要求用户提供一周中的某一天和开始日期。
我希望在开始日期之后的一周的第二天(这里没有问题)并将当周的退出事件更新到新的开始日(仍然没有问题)。然后我想在之后的事件发生后7天将所有其他事件增加。 (小于 - 问题)
<?php
session_start();
require_once '../../../config/db-config.php';
$weekday = $_POST['weekday']; // day of the week the event should take place on
$start_date = $_POST['start-date']; //new starting date of the event
if (date('N', strtotime($start_date)) == $weekday)
{
$start_date = $_POST['start-date'];
}
else
{
$start_date = date('Y-m-d', strtotime("next $weekday", strtotime($start_date))); //gets the first day of the week after the starting date. First event should start on this day.
}
$start_time = $_POST['start-time'];
$end_time = $_POST['end-time'];
$start = $start_date . " " . $start_time; //'yyyy-dd-mm hh:mm:ii' format
$end = $start_date . " " . $end_time;
$repeats = $_POST['repeats']; // 1 for repeats 0 for no repeats
$repeat_freq = $_POST['repeat-freq']; //7 for 7 days, 14 for 14 days etc
$parent_id = $_POST['parent-id']; //common parent_id to the event group
$stmt = $dbh->prepare("
UPDATE events
SET start = :start, end = :end
WHERE parent_id = :parent_id AND WEEK(start) =WEEK(:start)"); //This updates the existing event of that week to the new starting date
$stmt->bindParam(':start', $start);
$stmt->bindParam(':end', $end);
$stmt->bindParam(':parent_id', $parent_id);
$stmt->execute();
}
现在我需要在这个事件之后遍历每个事件(使用相同的parent_id)并将其递增7天(或者无论我的repeat_freq是什么)。我尝试过使用
UPDATE events
SET start = :start + INTERVAL 7 DAY, end = :end + INTERVAL 7 DAY
但这只会将所有事件更新为新开始日期后7天,而不是最后一次事件后7天。如果我可以把它放在一个循环中而不必引用特定的事件id而只是按顺序进行,那就太好了。我对任何解决方案持开放态度。谢谢你的阅读。
更新SCHEMA
我的parent_events表有
parent_id (auto increment) | start_date | repeats | repeat_freq |
我的事件表包含以下内容
event_id (auto increment) | parent_id | start | end |
创建新的周期性事件时,我在parent_events表中插入一行。我使用lastInsertId()获取新的parent_id,并在将所有重复实例(该父事件的事件)插入事件表时使用它。基本上,events表包含特定(父)事件的所有实例。
工作代码更新
$stmt = $dbh->prepare("
SELECT event_id
FROM events
WHERE parent_id = :parent_id AND WEEK(start) >=WEEK(:start)");
$stmt->bindParam(':start', $start_date);
$stmt->bindParam(':parent_id', $parent_id);
$stmt->execute();
$updateArray = array();
$last_class = 0;
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
if ($last_event != $row['event_id']) {
$last_event = $row['event_id'];
$updateArray[$last_event] = array('event_id' => $row['event_id']);
}
}
foreach($updateArray as $update){
$event_id = $update['event_id'];
$stmt = $dbh->prepare("
UPDATE events
SET title = start = :start, end=:end
WHERE event_id = :event_id");
$stmt->bindParam(':start', $start);
$stmt->bindParam(':end', $end);
$stmt->bindParam(':event_id', $event_id);
$stmt->execute();
$new_start = strtotime($start . '+' . $repeat_freq . 'DAYS');
$new_end = strtotime($end . '+' . $repeat_freq . 'DAYS');
$start = gmdate("Y-m-d H:i", $new_start);
$end = gmdate("Y-m-d H:i", $new_end);
}
答案 0 :(得分:1)
我认为最简单的方法是通过PHP循环SET事件。
我将在下面写下重要的代码:
$sql='SELECT event_id AS id from events WHERE parent_id=:parent_id AND start=:start
运行此查询将获得一个包含所有需要更新的ID的数组
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$row_date=array();
$row_date[0]=$start //get start date
foreach ($rows as $row)
$sql_date="SELECT TIMESTAMPADD(week,1,$row_date[0])"; //increment start date by 1 week
$date = $mysqli->query($sql_date);
$row_date = $result->fetch_array(MYSQLI_NUM); //Set the start date as Start date + 1 week to reflect in the next loop.
$sql_update="UPDATE events SET start=$row_date[0] WHERE event_id=$row['id']";
$mysqli->query($sql_update);
end foreach
代码我需要一些调整,但我认为它有助于支出这个想法。