Question

我为我的问题的简单性而道歉。

我正在通过“Hello World”，为孩子和初学者进行计算机编程 - 由Warren和Carter Sande工作。

第一章的第二个例子是这个数字例子，是一个盗版数测验。编程语言是Python。

它应该允许6次猜测，除非首先猜到正确的数字。我想对你们来说，代码可以自我解释。

import random

secret = random.randint(1,99)
guess = 0
tries = 0

print "AHOY! I'm the dread Pirate Roberts, and I have a secret!"
print "It's a number from 1 to 99. I'll give you 6 tries."

while guess != secret and tries < 6:
guess = input("What's yer guess? ")
if guess < secret:
    print "Too low, ye scurvy dog!"
elif guess > secret:
    print "Too high, landlubber!"
tries = tries +1
if guess == secret:
    print "Avast! Ye got it! Found my secret, ye did!"
else:
    print "No more guesses! Better luck next time, matey!"
    print "The secret number was", secret

但是当我运行它时，它会告诉我每次猜测后的答案是什么，这是不应该的。它应该等到最后。

我无法弄清楚我做错了什么。我检查了每一行，或者至少，我认为我有。

如果有人能够指出我出错的地方，那就太棒了。

Answer 1

正确的缩进是关键。确保你缩进循环内的东西，并在循环后缩进后留下东西。

while guess != secret and tries < 6:
    guess = input("What's yer guess? ")
    if guess < secret:
        print "Too low, ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found my secret, ye did!"
else:
    print "No more guesses! Better luck next time, matey!"
    print "The secret number was", secret

Answer 2

更好的方法是写这个。然后，您不必在循环外将guess设置为0

for tries in range(1, 6):
    guess = input("What's yer guess? ")
    if guess < secret:
        print "Too low, ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    else:
        print "Avast! Ye got it! Found my secret, ye did!"
        break 
else:
    print "No more guesses! Better luck next time, matey!"
    print "The secret number was", secret

Python示例在测验期间重复回答而不是结束

2 个答案: