php mysql查询语法

Question

我的桌子上有这些字段

month
year

我想根据此

进行查询

month BETWEEN 4 AND 12 AND year = 2008

OR

month BETWEEN 1 AND 10 AND year is greater than 2008 but equal or less than 2009

我试过了，但没有给出正确的查询结果。

"WHERE month BETWEEN 4 AND 12 AND year = 2008 OR month BETWEEN 1 AND 10 AND year 2008<=2009";

注意：这里的数字是可变的，我显示实际的数字让你轻松理解:) 有什么帮助吗？

  

year =（2008＆lt; = 2009）意味着年份必须大于2008但等于或小于2009

Answer 1

试试这个：

where (year*100)+month between  200804 and  200910

这将照顾所有场景..即使这些年份之间的差异不止一个

Answer 2

"WHERE ((month BETWEEN 4 AND 12) AND year = 2008) OR ((month BETWEEN 1 AND 10) AND (year 2008 OR 2009))";

希望它有所帮助：）

Answer 3

你应该这样做，

WHERE (year = 2008 AND month BETWEEN 4 AND 12) 
       OR
      (year > ? AND year <= 2009 AND 
       month BETWEEN 1 AND 10)

这是什么意思？ greater than 2008 but equal or less than 2009。你的意思是等于2009吗？

Answer 4

你看过MySQL Date Functions了吗？这样做就像试着用鞋钉在钉子上。

Answer 5

它应该像这样工作：

WHERE ((month BETWEEN 4 AND 12) AND year = 2008) OR ((month BETWEEN 1 AND 10) AND year = 2009)