我有3张桌子:
CREATE TABLE "Names" (
"Name" TEXT(20) NOT NULL,
"Gender" TEXT(20) NOT NULL,
PRIMARY KEY ("Name", "Gender")
);
CREATE TABLE "Snames" (
"Sname" TEXT(20) NOT NULL,
PRIMARY KEY ("Sname")
);
CREATE TABLE "People" (
"ID" INTEGER NOT NULL,
"Name" TEXT(20) NOT NULL,
"Sname" TEXT(20) NOT NULL,
"Gender" TEXT(1) NOT NULL,
"FatherID" INTEGER,
"MotherID" INTEGER,
PRIMARY KEY ("ID") ,
CONSTRAINT "Father" FOREIGN KEY ("FatherID") REFERENCES "People" ("ID"),
CONSTRAINT "Mother" FOREIGN KEY ("MotherID") REFERENCES "People" ("ID"),
CONSTRAINT "Sname" FOREIGN KEY ("Sname") REFERENCES "Snames" ("Sname"),
CONSTRAINT "Name" FOREIGN KEY ("Name", "Gender") REFERENCES "Names" ("Name", "Gender")
);
我的问题是“FatherID”和“MotherID”的外键约束,它引用了自己的表。是否可以只允许“M”在“FatherID”的“性别”列中,而“F”表示“MotherID”?是否有可能不允许母亲/父亲引用同一行?
基本上:父亲必须是男性。妈妈一定是女性。你不能成为自己的母亲/父亲。
答案 0 :(得分:3)
我相信SQLite不支持包含具有从其他行动态获取的值的表达式的约束,但外键是明显的例外。
您必须创建触发器以检查父亲和母亲的性别。
使用此表定义:
CREATE TABLE "People" (
"ID" INTEGER NOT NULL,
"Name" TEXT(20) NOT NULL,
"Sname" TEXT(20) NOT NULL,
"Gender" TEXT(1) NOT NULL,
"FatherID" INTEGER,
"MotherID" INTEGER,
PRIMARY KEY ("ID") ,
CONSTRAINT "Father" FOREIGN KEY ("FatherID") REFERENCES "People" ("ID"),
CONSTRAINT "Mother" FOREIGN KEY ("MotherID") REFERENCES "People" ("ID"),
CHECK (Gender IN ('M', 'F')),
CHECK ("ID" NOT IN ("FatherID", "MotherID")));
这可能是INSERT触发器(我让你写UPDATE):
CREATE TRIGGER checkParentIdsOnInsert BEFORE INSERT ON People
WHEN new.FatherID IS NOT NULL OR new.MotherID IS NOT NULL
BEGIN
SELECT CASE
WHEN ((SELECT Gender FROM People AS t1 WHERE t1.ID=new.FatherID) = 'F'
AND (SELECT Gender FROM People AS t2 WHERE t2.ID=new.MotherID) = 'M')
THEN RAISE(ABORT, 'Father must be male and mother female')
WHEN ((SELECT Gender FROM People AS t3 WHERE t3.ID=new.FatherID) = 'F')
THEN RAISE(ABORT, 'Father must be male')
WHEN ((SELECT Gender FROM People AS t4 WHERE t4.ID=new.MotherID) = 'M')
THEN RAISE(ABORT, 'Mother must be female')
END;
END;
一些简单的测试:
sqlite> pragma foreign_keys=on;
sqlite> INSERT INTO People (Name, SName, Gender, FatherID, MotherID) VALUES
...> ("Jo", "Blo", "M", NULL, NULL);
sqlite> INSERT INTO People (Name, SName, Gender, FatherID, MotherID) VALUES
...> ("Za", "Bla", "F", NULL, NULL);
sqlite> INSERT INTO People (Name, SName, Gender, FatherID, MotherID) VALUES
...> ("Bad", "Kid", "M", 2, 1);
Error: Father must be male and mother female
sqlite> INSERT INTO People (Name, SName, Gender, FatherID, MotherID) VALUES
...> ("Bad", "Kid", "M", 2, NULL);
Error: Father must be male
sqlite> INSERT INTO People (Name, SName, Gender, FatherID, MotherID) VALUES
...> ("Bad", "Kid", "M", NULL, 1);
Error: Mother must be female
sqlite> INSERT INTO People (Name, SName, Gender, FatherID, MotherID) VALUES
...> ("Good", "Kid", "M", 1, 2);
sqlite> .headers on
sqlite> .mode column
sqlite> SELECT * FROM People;
ID Name Sname Gender FatherID MotherID
---------- ---------- ---------- ---------- ---------- ----------
1 Jo Blo M
2 Za Bla F
3 Good Kid M 1 2
答案 1 :(得分:2)
以下应该可以工作但是需要一些其他冗余的外键列(SQL Fiddle)
CREATE TABLE "People" (
"ID" INTEGER NOT NULL,
"Name" TEXT(20) NOT NULL,
"Sname" TEXT(20) NOT NULL,
"Gender" TEXT(1) NOT NULL,
"FatherID" INTEGER NULL,
"FatherGender" TEXT(1) NULL,
"MotherID" INTEGER NULL,
"MotherGender" TEXT(1) NULL,
PRIMARY KEY ("ID") ,
UNIQUE ("ID", "Gender"),
CHECK ("ID" NOT IN ("FatherID", "MotherID")),
CHECK ("FatherGender" = 'M'),
CHECK ("MotherGender" = 'F'),
CONSTRAINT "Father" FOREIGN KEY ("FatherID","FatherGender") REFERENCES "People" ("ID", "Gender"),
CONSTRAINT "Mother" FOREIGN KEY ("MotherID","MotherGender") REFERENCES "People" ("ID", "Gender")
);
INSERT INTO "People"
VALUES(1, 'Adam', '?', 'M', NULL, NULL, NULL, NULL);
INSERT INTO "People"
VALUES(2, 'Eve', '?', 'F', NULL, NULL, NULL, NULL);
INSERT INTO "People"
VALUES(3, 'Cain', '?', 'M', 1, 'M', 2, 'F');
答案 2 :(得分:1)
要应用此类约束, 您需要使用可以完成工作的 触发器
编辑:SQLite支持触发器。谢谢@catcall