我有一张看起来像这样的表:
table: Q
---------------------------
|question| scope | type |
---------------------------
| this | A | 1 |
| that | A | 1 |
| them | A | 1 |
---------------------------
| this | A | 2 |
| that | A | 2 |
| them | A | 2 |
---------------------------
| this | B | 1 |
| that | B | 1 |
| them | B | 1 |
---------------------------
我需要一个范围,我需要从每种类型中提取两个条目。如果范围是A,则可能的解决方案可能是:
---------------------------
| this | A | 1 |
| them | A | 1 |
---------------------------
| that | A | 2 |
| this | A | 2 |
---------------------------
我目前正在使用以下SQL语句:
SELECT tmp.question, tmp.type, tmp.scope
FROM Q
LEFT JOIN (
SELECT * FROM Q ORDER BY RAND( )
)tmp ON ( Q.type = tmp.type AND tmp.scope = 'A' )
GROUP BY tmp.type
ORDER BY Q.type
然而,这只会返回每个类型一个条目,并且由于某种原因会返回NULL行。
因此,我的问题是如何优化语句以返回两行并消除NULL行?
答案 0 :(得分:2)
您可以将等级从2更改为您希望为每个类别获得的任何内容。
http://www.sqlfiddle.com/#!2/f3946/86
试试这个:
SELECT x.question,
x.scope,
x.type
FROM (
SELECT bp.question, bp.scope, bp.type,
CASE WHEN bp.type = @type
THEN @rownum := @rownum + 1
ELSE @rownum := 1
END AS rank,
@type := bp.type
FROM (select * from Q order by rand()) bp
JOIN (SELECT @rownum := 0, @type := NULL) r
WHERE bp.scope = 'A'
ORDER BY type
) x
WHERE x.rank <= 2
order by x.type
注意:我使用旧答案并进行了随机化改进。 我得到帮助的老答案是: Select N records for each category and order by X
答案 1 :(得分:0)
<强> SqlFiddle 强>:
(
SELECT question, scope, type FROM Q
WHERE scope = 'A' AND type = 1
ORDER BY RAND() LIMIT 2
)
UNION
(
SELECT question, scope, type FROM Q
WHERE scope = 'A' AND type = 2
ORDER BY RAND() LIMIT 2
)