Question

我刚刚开始学习mysqli（20分钟前），我对某些事感到困惑。在下面的示例中，我可以将数据插入服务器。如何使函数在成功时返回true，在失败时返回false。如果if语句为真，并且在else语句中为return true，或者它是否比那更高级，那么它就像替换return false一样简单吗？如果我想在成功时返回true而在失败时返回false，我还需要写什么？

function insert($firstName, $lastName) {
   if ($stmt = $mysqli->prepare("INSERT INTO CodeCall (FirstName, LastName) values (?, 

   ?)")) {

/* Bind our params */
$stmt->bind_param('ss', $firstName, $lastName);


/* Execute the prepared Statement */
$stmt->execute();

/* Echo results */
echo "Inserted {$lastName},{$firstName} into database\n";

/* Set our params for second query */
$firstName = "John";
$lastName  = "Ciacia";

/* Execute second Query */
$stmt->execute();

    return true;

/* Close the statement */
$stmt->close(); 
    }
    else {
/* Error */
return false;
    }}

Answer 1

使用execute方法执行INSERT查询（也是UPDATES和DELETES查询）时，成功时返回TRUE，失败时返回FALSE。所以你可以这样做：

function insert($firstName, $lastName) {
    $stmt = $mysqli->prepare("INSERT INTO CodeCall (FirstName, LastName) values (?, ?)");

    /* Bind our params */
    $stmt->bind_param('ss', $firstName, $lastName);

    /* Execute the prepared Statement */
    if ( $stmt->execute() ) {
        /* Echo results */
        echo "Inserted {$lastName},{$firstName} into database\n";

        /* Set our params for second query */
        $firstName = "John";
        $lastName  = "Ciacia";

        /* Execute second Query */
        $stmt->execute();

        $result = true;
    } else {
        /* Error */
        $result = false;
    }

    /* Close the statement */
    $stmt->close(); 

    return $result;
}

在准备好的陈述上回答正确或错误

1 个答案: