Question

我有两张桌子：登录and关注。

表名：login
字段：id,email,username,imageurl
表名：follow
字段：id:user_id:follow_id

这就像Twitter粉丝的概念。我希望获取myfollower名称的详细信息以及myfollower以下人员姓名的详细信息。

为此，我编写了如下编码。

public function follw ()
{
    if( $this->input->get("userid")  )

     {          

    extract($this->input->get()); 

    $followers_list = array();

    $follower = array();

    $query = $this->db->query('select follow_id from follow where user_id = '.$userid.'')->result();

    foreach($query as $row)

    { 
        $follower['follower_id'] = $row->follow_id;

        if($follower['follower_id'] == "")
        {
            echo "hi";
        }

        else
            {
        $query3 = $this->db->query('select username from login where id = '.$follower['follower_id'].'')->result();

        foreach($query3 as $row3)

            {
                $follower['followuser'] = $row3->username;
            }

        $query1 = $this->db->query('select follow_id from follow where user_id = '.$follower['follower_id'].'')->result();

        foreach($query1 as $row1)

            {
                $follower['follow_id'] = $row1->follow_id;

            if($follower['follow_id'] == "")

            {
                echo "jeeva";
                }


            else
            {
        $query2 = $this->db->query('select username from login where id = '.$follower['follow_id'].'')->result();

        foreach($query2 as $row2)

            {
                $follower['username'] = $row2->username;


            }

            }//second for each in else loop
            }//first foreach in else loop

            }//main else
        $followers_list[] = $follower;

        }

        $str = json_encode($followers_list);
    echo stripslashes($str);
}

else
{
    echo '[{"status":"Failure  - Error Occured - Not Enough Details provided"}]';

    }
}

我得到这样的输出：

[{"follower_id":"12","followuser":"janmejoy","follow_id":"24","username":"sarvana"},{"follower_id":"10","followuser":"jeeva","follow_id":"23","username":"selva"},{"follower_id":"6","followuser":"raj","follow_id":"17","username":"jeeva"},{"follower_id":"23","followuser":"selva","follow_id":"22","username":"guru"}]

此输出显示myfollower的姓名和myfollower以下的人名，但问题是它只显示myfollower以下人名的一名成员。

但是，我希望输出如下：

[{"follower_id":"12","followuser":"janmejoy",{"follow_id":"24","username":"sarvana",follow_id":"13","username":"jai",follow_id":"9","username":"raj"}},{"follower_id":"10","followuser":"jeeva","follow_id":"23","username":"selva"},{"follower_id":"6","followuser":"raj","follow_id":"17","username":"jeeva"},{"follower_id":"23","followuser":"selva","follow_id":"22","username":"guru"}]

Answer 1

[{ “follower_id”： “12”， “followuser”： “janmejoy”，{ “follow_id”： “24”， “用户名”： “sarvana”，follow_id “：” 13" ， “用户名”：” JAI “follow_id ”：“ 9" ， ”用户名“： ”拉吉“}}，{ ”follower_id“： ”10“， ”followuser“： ”jeeva“， ”follow_id“： ”23“， ”用户名“：”热带雨林 “}，{” follower_id “：” 6" ， “followuser”： “拉吉”， “follow_id”： “17”， “用户名”： “jeeva”}，{ “follower_id”： “23”， “followuser” ： “热带雨林”， “follow_id”： “22”， “用户名”： “大师”}]

此代码是无效的JSON变量。我无法为你解决这个问题。请更新您的问题。

如何在单个数组中显示更多数组结果？

1 个答案: