如何在mysql中获取所有类似的命名记录

时间:2012-08-31 12:51:23

标签: php mysql

我有一个包含数据的表格,如:

product_name | quantity | tert
ASIZ A4 100 FOX | 20| BUYER1
CERVEZA A6 150 FOX | 15| BUYER1
ASIZ A4 150 FOX | 40| BUYER1   
CERVEZA A6 11 FOX | 15| BUYER1
QUINTA A6 150 FOX | 15| BUYER2
ASIZ A4 150 FOX | 33 | BUYER2
ASIZ A6 150 FOX | 15| BUYER2
CERVEZA A6 150 FOX | 15| BUYER2

我想检索与第一个单词匹配的所有数据(例如 ASIZ )对数量求和并显示如下:

BUYER1
Asiz - 60 pcs.
Cerveza = 30 pcs.
etc.

BUYER2
Asiz = 48 pcs.
Cerveza = 15 pcs.

目前我正在使用2个循环:

SELECT DISTINCT product_name 
FROM my_table 
WHERE buyer_code= '".$bcode."' 
GROUP BY product_name

- 我得到产品名称

然后

SELECT DISTINCT product_name,tert, SUM(quantity) AS quantity 
FROM my_table 
WHERE buyer_code ='".$bcode."' AND 
      prouct_name LIKE '".$first_word_of_product_name."%' 
GROUP BY tert
ORDER BY data ASC

我得到了正确的金额,但每当它找到类似的命名产品时就会列出它们(例如: BUYER1:ASIZ - 2次等)

它显示:

Buyer1
ASIZ - 60
Cerveza - 30
ASIZ - 60
Cerveza - 30

我知道它与product_name有关,但是我应该如何编写sql语句呢? 谢谢

3 个答案:

答案 0 :(得分:1)

SELECT SUBSTRING_INDEX(product_name, '.', 1) product, tert, SUM(quantity) quantity
FROM my_table
GROUP BY product, tert

答案 1 :(得分:0)

从第二个sql中删除tert,它将按预期工作。

将此更改为

SELECT DISTINCT product_name,tert, SUM(quantity) AS quantity 
FROM my_table 
WHERE buyer_code ='".$bcode."' 
     AND prouct_name LIKE '".$first_word_of_product_name."%' 
GROUP BY tert 
ORDER BY data ASC

SELECT DISTINCT product_name, SUM(quantity) AS quantity 
FROM my_table 
WHERE buyer_code ='".$bcode."' 
     AND prouct_name LIKE '".$first_word_of_product_name."%' 
GROUP BY product_name 
ORDER BY data ASC

答案 2 :(得分:0)

运行

SELECT tert, SUBSTRING_INDEX(product_name,' ',1) as product, sum(quantity) as qty
FROM my_table 
GROUP BY tert, product
ORDER BY tert, product

您的结果按 tert 排序,因此您可以逐个展示产品数量并显示 tert 每次 tert 改变。

<强>更新: 代码示例如何输出数据(未测试):

$tert = null;
foreach($rows as $row){
    if($rows['tert'] != $tert){
        $tert = $rows['tert'];
        echo $tert;
    }
    echo $row['product'], "-", $row['qty'];
}

此处$rows - 所有已获取的行。