Question

这是我的PHP邮件代码：

if ($_POST) {
    $email=$_POST['email'];
    $subject=$_POST['subject'];
    $budget=$_POST['budget'];
    $text=$_POST['text'];
    $to="hello@mymail.com";

    mail($to, "Piece of Cake = ".$subject, $text, "Budget:".$budget, "From:".$email );
}

这是我的AJAX电子邮件功能：

$(function (){
    $('button#send_brief').click(function(){
        var email = $('#brief_email');
        var subject = $('#brief_type');
        var budget = $('#brief_budget');
        var text = $('#brief_comments');
        var emailerData = 'email' + email +'&subject' + subject + '&budget' + budget+ '&text' + text;

        if(text=='') {
            $('#brief_email').css({'background-color':'red'});
         }
         else {

        $.ajax({
            type: "POST",
            url:"emailer.php",
            data: emailerData,
            success: function(){
                $('.success').fadeIn(1000);
                setTimeout (function(){
                $('.brief').slideUp({
                    duration: 1000,
                    easing: 'easeInSine'});}
                            ,2000);
                setTimeout (function(){
                $('#brief').fadeIn();}
                            ,3000);
                setTimeout (function(){
                $('.success').fadeOut(1000);}
                            ,2000);
            }

        });

        return false;}
    });   

});

这是我的表格：

<form method="POST" action="" >
<fieldset>

            <label for="brief_email">Your email</label>
            <input type="text" id="brief_email" placeholder="your contact email here"/>
             etc ...
</fieldset>
</form>
<button id="send_brief">Send it</button>

首先，当我将所有字段留空时，它仍会显示成功屏幕。第二，即使输入有效数据，我也不会收到发送的电子邮件。

我已多次查看代码，对我来说似乎没问题。

请帮我找到我错的地方。

Answer 1

你的问题出在AJAX构造中，你缺乏价值：val()

var email = $('#brief_email').val();
var subject = $('#brief_type').val();
var budget = $('#brief_budget').val();
var text = $('#brief_comments').val();

如果没有val()，您将向PHP脚本发送一个对象而不是值。

vars构建你缺少=

var emailerData = 'email=' + email +'&subject=' + subject + '&budget=' + budget+ '&text=' + text;

您的mail()构造也很糟糕，您无法发送任何其他值，而不是检查mail()。您检查$_POST，$_POST始终为真，您需要检查至少一个帖子值。

<?php

if (isset($_POST['email'])) {
    $email=$_POST['email'];
    $subject=$_POST['subject'];
    $budget=$_POST['budget'];
    $text=$_POST['text'];
    $to      = 'mail@example.com';

    $subject = "Piece of Cake = ".$_POST['subject'];
    $message = "New message from website

    Email: $email
    Budget: $budget
    Comments: $text";

    $headers = 'From: ' . $email . "\r\n" .
        'Reply-To: ' . $email . "\r\n" .
        'X-Mailer: PHP/' . phpversion();

    mail($to, $subject, $message, $headers);
}
?>

Answer 2

您需要查看发送的电子邮件

if ($_POST) {
    $email=$_POST['email'];
    $subject=$_POST['subject'];
    $budget=$_POST['budget'];
    $text=$_POST['text'];
    $to="hello@mymail.com";

    if(mail($to, "Piece of Cake = ".$subject, $text, "Budget:".$budget, "From:".$email )) echo '1';
    else echo '0';

}

检查ajax响应中的电子邮件发送响应

$(function (){
    $('button#send_brief').click(function(){
        var email = $('#brief_email');
        var subject = $('#brief_type');
        var budget = $('#brief_budget');
        var text = $('#brief_comments');
        var emailerData = 'email' + email +'&subject' + subject + '&budget' + budget+ '&text' + text;

        if(text=='') {
            $('#brief_email').css({'background-color':'red'});
         }
         else {

        $.ajax({
            type: "POST",
            url:"emailer.php",
            data: emailerData,
            success: function(result){
            if(result == 1){
    $('.success').fadeIn(1000);
                setTimeout (function(){
                $('.brief').slideUp({
                    duration: 1000,
                    easing: 'easeInSine'});}
                            ,2000);
                setTimeout (function(){
                $('#brief').fadeIn();}
                            ,3000);
                setTimeout (function(){
                $('.success').fadeOut(1000);}
                            ,2000);
}
            }

        });

        return false;}
    });   

});

Answer 3

您的电子邮件发送代码有两个问题：

mail($to, "Piece of Cake = ".$subject, $text, "Budget:".$budget, "From:".$email );

第一个问题是你没有检查返回值：

if (false === mail( ... )) { echo "Yelp! Mail not sent"; }

第二个问题是您的电子邮件标题应合并到第四个参数中：

mail($to, "Piece of Cake = ".$subject, $text, "Budget: $budget\r\nFrom: $email");

那是因为第五个参数适用于sendmail，它不是电子邮件标题的另一个字段。

AJAX / PHP电子邮件发送者不发送电子邮件

3 个答案: