SQL Fiddle Demo

Question

好的我有一张看起来像这样的表

ItemID | ColumnName | Value
1      | name       | Peter
1      | phone      | 12345678
1      | email      | peter@host.com
2      | name       | John
2      | phone      | 87654321
2      | email      | john@host.com
3      | name       | Sarah
3      | phone      | 55667788
3      | email      | sarah@host.com

现在我需要把它变成这个：

ItemID | name  | phone    | email
1      | Peter | 12345678 | peter@host.com
2      | John  | 87654321 | john@host.com
3      | Sarah | 55667788 | sarah@host.com

我一直在研究动态数据透视示例，但似乎我无法将它们融入我的场景中。

有人可以帮忙吗？

Answer 1

看一下以下示例

CREATE TABLE #Table (
        ID INT,
        ColumnName VARCHAR(250),
        Value VARCHAR(250)
)

INSERT INTO #Table SELECT 1,'name','Peter' 
INSERT INTO #Table SELECT 1,'phone','12345678' 
INSERT INTO #Table SELECT 1,'email','peter@host.com' 
INSERT INTO #Table SELECT 2,'name','John' 
INSERT INTO #Table SELECT 2,'phone','87654321' 
INSERT INTO #Table SELECT 2,'email','john@host.com' 
INSERT INTO #Table SELECT 3,'name','Sarah' 
INSERT INTO #Table SELECT 3,'phone','55667788' 
INSERT INTO #Table SELECT 3,'email','sarah@host.com' 

---I assumed your tablename as TESTTABLE--- 
DECLARE @cols NVARCHAR(2000) 
DECLARE @query NVARCHAR(4000) 

SELECT  @cols = STUFF(( SELECT DISTINCT TOP 100 PERCENT 
                                '],[' + t.ColumnName 
                        FROM    #Table AS t 
                        --ORDER BY '],[' + t.ID 
                        FOR XML PATH('') 
                      ), 1, 2, '') + ']' 

SELECT  @cols

SET @query = N'SELECT ID,'+ @cols +' FROM 
(SELECT t1.ID,t1.ColumnName , t1.Value FROM #Table AS t1) p 
PIVOT (MAX([Value]) FOR ColumnName IN ( '+ @cols +' )) 
AS pvt;' 

EXECUTE(@query)

DROP TABLE #Table

Answer 2

试试这个：

SQL Server 2005 +

 ;with 
        cte_name  as(select * from <table> where ColumnName='name'),
        cte_phone as(select * from <table> where ColumnName='phone'),
        cte_email as(select * from <table> where ColumnName='email')
  select n.ItemID,n.Value [Name],p.Value [Phone],e.Value [Email] 
  from  cte_name n
  join  cte_phone p
  on    n.ItemID=p.ItemID
  join  cte_email e
  on    n.ItemID=e.ItemID

SQL Fiddle Demo

Answer 3

您不需要动态数据透视，因为它将是一个不同的表。简单地做这样的事情：

name    phone   email
---------------------------------
Peter            
        123456
                 peter@host.com

选中此SQL fiddle

SELECT DISTINCT u.ItemID, n.Value as 'name', p.Value as 'phone', e.Value as 'email'
FROM UserData u
INNER JOIN(
SELECT ItemID, Value 
FROM UserData WHERE ColumnName = 'name') n ON n.ItemID = u.ItemID
INNER JOIN(
SELECT ItemID, Value 
FROM UserData WHERE ColumnName = 'phone') p ON p.ItemID = u.ItemID
INNER JOIN(
SELECT ItemID, Value 
FROM UserData WHERE ColumnName = 'email') e ON e.ItemID = u.ItemID

Answer 4

这是我用于我的联系人列表的查询：）

SELECT *
FROM
    (
    SELECT Contact_Id AS CT
          , [Age]
          , [Sex]
          , [State]
          , [Country]
          , [Keyword]
          , [Married]
          , [Kids]
          , [Car]
     FROM
         (SELECT c.PropertyName
               , c.ValueString
               , c.Contact_Id
          FROM
              ContactProfiles c) AS ctp
         PIVOT (max(ctp.ValueString) FOR PropertyName IN ([Age], [Sex], [State], [Country], [Keyword], [Married], [Kids], [Car])) AS PivotTable
         ) AS pvt

WHERE
    pvt.[Age] > 18
    AND (pvt.[State] = 'CA' OR pvt.[State] = 'NY')
    AND pvt.[Sex] = 'F'
    --*AND pvt.[Keyword] LIKE '%B;%'
    AND pvt.[Married] = 'True'
    AND pvt.[Kids] > 0

Answer 5

你试过这个：

SELECT ItemID, name, phone, email
FROM
(SELECT [ItemID] ,[ColumnName] ,[Value] FROM Item) Item
PIVOT (MAX(Value) FOR ColumnName IN (name, phone, email) ) as pvt

T-SQL动态数据透视

5 个答案:

SQL Fiddle Demo