Question

我试图建立一种关系，允许多个实体定期更新项目。更准确地说，我想定义模型中使用的术语。

Lead =＆gt;这将是项目。

公司=＆gt;允许对项目进行投标的承包商。在对项目进行投标/谈判时，他们必须定期更新领导的状态字段。

潜在客户更新=＆gt;表用于保持更新。

但是当我尝试运行服务器时，我收到此错误

"companies.leadupdate: Reverse query name for field 'lead' clashes with m2m field 'Lead.leadupdate'. Add a related_name argument to the definition for 'lead'"

我决定基于Django网站https://docs.djangoproject.com/en/1.4/topics/db/models/上的示例走这条路线，这与我想要实现的类似。我可能也完全关闭了：）

from django.db import models
class Company(models.Model):
    comp_name = models.CharField(max_length=200)
    comp_address = models.CharField(max_length=200)
    comp_email = models.CharField(max_length=200)
    comp_zip = models.IntegerField()
    comp_phone = models.IntegerField()
    comp_city = models.CharField(max_length=40)
    def __unicode__(self):
        return self.comp_name



class Leadsource(models.Model):
    assetname = models.CharField(max_length=100)
    def __unicode__(self):
        return self.assetname


class Lead(models.Model):

    numberofstations = models.IntegerField()
    comment = models.CharField(max_length=500)
    #company = models.ManyToManyField(Company)
    leadsource = models.ForeignKey(Leadsource)
    submissiondate = models.DateField('Submission Date')
    cname = models.CharField('Business Name', max_length=100)
    crep = models.CharField('Principle Contact', max_length=100)
    cemail = models.CharField(max_length=100)
    caddress = models.CharField(max_length=100)
    cnumber = models.CharField(max_length=100)
    leadupdate = models.ManyToManyField(Company,through='Leadupdate')

    def __unicode__(self):
        return u"%s %s %s" % (self.cname, self.crep, self.leadsource)


class Leadupdate(models.Model):
    updatedate = models.DateField()
    update = models.CharField(max_length=400)
    updatefrom = models.ForeignKey(Company)
    lead = models.ForeignKey(Lead)
    def __unicode__(self):
        return u" %s - %s " % (self.update, self.updatedate)

Answer 1

与错误一样，尝试将related_name参数添加到Lead字段的定义中，例如：

lead = models.ForeignKey(Lead, related_name="lead_related")

这应该可以解决问题。

Django中间模型

1 个答案: