Question

我真的需要帮助。代码结果为2:0:0，格式设置为hh:mm:ss。我希望结果为2:00:00（在0下的分钟和秒之前添加10。

NSDateFormatter *test = [[NSDateFormatter alloc] init];
[test setDateFormat:@"HH:mm:ss"];
NSDate *date1 = [test dateFromString:@"18:00:00"];
NSDate *date2 = [test dateFromString:@"20:00:00"];
NSCalendar* gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
unsigned int uintFlags =  NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit;
NSDateComponents* differenceComponents = [gregorian components:uintFlags fromDate:date1 toDate:date2 options:0];

NSLog(@"%d:%d:%d",[differenceComponents hour],[differenceComponents minute],[differenceComponents second]);

怎么做？

Answer 1

使用%02ld说明符进行记录，例如：

NSLog(@"%ld:%02ld:%02ld",[differenceComponents hour],[differenceComponents minute],[differenceComponents second]);

输出：

2:00:00

另外像这样创建NSStrings：

NSString *theString = [NSString stringWithFormat:@"%ld:%02ld:%02ld",[differenceComponents hour],[differenceComponents minute],[differenceComponents second]];
NSLog(@"%@",theString);

Answer 2

问题是：00-00为0。我曾经遇到过这个问题并且像这样解决了它

-(NSString*)formatIntToString:(int)inInt{
if (inInt <10) {
    NSString *theString = [NSString stringWithFormat:@"0%d",inInt];
    return theString;
}
else {
    NSString *theString = [NSString stringWithFormat:@"%d",inInt];
    return theString;
}}

在NSLog中使用它：

NSLog(@"%@:%@:%@",[self formatIntToString:[differenceComponents hour]],[self formatIntToString:[differenceComponents minute]],[self formatIntToString:[differenceComponents second]]);

NSDateComponents的NSLog分钟和秒 - 如何显示前导零？

2 个答案: