Question

我有以下代码来使用谷歌图片搜索API：

google.load('search', '1');   
    function searchComplete(searcher) {
      // Check that we got results
      if (searcher.results && searcher.results.length > 0) {
        // Grab our content div, clear it.
        var contentDiv = document.getElementById('contentimg');
        contentDiv.innerHTML = '';

        // Loop through our results, printing them to the page.
        var results = searcher.results;
        for (var i = 1; i < results.length; i++) {
          // For each result write it's title and image to the screen
          var result = results[i];
          var imgContainer = document.createElement('div');



          var newImg = document.createElement('img');
          // There is also a result.url property which has the escaped version
          newImg.src = result.tbUrl;


          imgContainer.appendChild(newImg);

          // Put our title + image in the content
          contentDiv.appendChild(imgContainer);

问题是，它给了我3个图像结果。如何打破一个循环并只显示第一个而不是3个图像？如果我将for (var i = 1; i < results.length; i++)更改为for (var i = 3; i < results.length; i++)它只显示一张图片，但显示的图片是第3张，我需要显示第1张图片:) 请建议

Answer 1

根本不要使用for循环。只需将i的所有实例替换为0。

google.load('search', '1');   
    function searchComplete(searcher) {
      // Check that we got results
      if (searcher.results && searcher.results.length > 0) {
        // Grab our content div, clear it.
        var contentDiv = document.getElementById('contentimg');
        contentDiv.innerHTML = '';

        var result = searcher.results[0];

        var imgContainer = document.createElement('div');

        var newImg = document.createElement('img');
        // There is also a result.url property which has the escaped version
        newImg.src = result.tbUrl;

        imgContainer.appendChild(newImg);

        // Put our title + image in the content
        contentDiv.appendChild(imgContainer);

0表示返回的第一个项目（编程中的几乎所有数字序列都从0开始！）所以其他所有结果都将被忽略。

Answer 2

使用break statement。一旦找到图像，它将终止循环，因此您将只有第一个。

      for (var i = 1; i < results.length; i++) {
      // For each result write it's title and image to the screen
      var result = results[i];
      var imgContainer = document.createElement('div');



      var newImg = document.createElement('img');
      // There is also a result.url property which has the escaped version
      newImg.src = result.tbUrl;


      imgContainer.appendChild(newImg);

      // Put our title + image in the content
      contentDiv.appendChild(imgContainer);
       //Berore the end of the loop
      if(i==1)
      {
      break;
      }
   }

Answer 3

当你只想要一个元素时，你不需要for循环。您可以使用

访问数组的第一个元素

result = results[0];

数组是从零开始的。因此，当它包含三个图像时，图像被命名为结果[0]，结果[1]和结果[2]。

打破javascript循环

3 个答案: