如何在java中将org.w3c.dom.Element输出为字符串格式?

时间:2009-08-02 19:21:53

标签: java xml dom

我有一个org.w3c.dom.Element对象传递给我的方法。我需要查看整个xml字符串,包括其子节点(整个对象图)。我正在寻找一种方法,可以将Element转换为我可以System.out.println的xml格式字符串。 “元素”对象上的println()将无效,因为toString()不会输出xml格式,也不会通过其子节点。没有编写自己的方法来做到这一点有一个简单的方法吗?感谢。

7 个答案:

答案 0 :(得分:152)

假设你想坚持使用标准API ......

您可以使用DOMImplementationLS

Document document = node.getOwnerDocument();
DOMImplementationLS domImplLS = (DOMImplementationLS) document
    .getImplementation();
LSSerializer serializer = domImplLS.createLSSerializer();
String str = serializer.writeToString(node);

如果<?xml version =“1.0”encoding =“UTF-16”?>宣言困扰你,你可以使用transformer代替:

TransformerFactory transFactory = TransformerFactory.newInstance();
Transformer transformer = transFactory.newTransformer();
StringWriter buffer = new StringWriter();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
transformer.transform(new DOMSource(node),
      new StreamResult(buffer));
String str = buffer.toString();

答案 1 :(得分:14)

String

获取<?xml version="1.0" encoding="UTF-16"?> 而不使用xml-declaration org.w3c.dom.Element)的简单4行代码
DOMImplementationLS lsImpl = (DOMImplementationLS)node.getOwnerDocument().getImplementation().getFeature("LS", "3.0");
LSSerializer serializer = lsImpl.createLSSerializer();
serializer.getDomConfig().setParameter("xml-declaration", false); //by default its true, so set it to false to get String without xml-declaration
String str = serializer.writeToString(node);

答案 2 :(得分:2)

如果你有XML的模式或者可以为它创建JAXB绑定,你可以使用JAXB Marshaller写入System.out:

import javax.xml.bind.*;
import javax.xml.bind.annotation.*;
import javax.xml.namespace.QName;

@XmlRootElement
public class BoundClass {

    @XmlAttribute
    private String test;

    @XmlElement
    private int x;

    public BoundClass() {}

    public BoundClass(String test) {
        this.test = test;
    }

    public static void main(String[] args) throws Exception {
        JAXBContext jxbc = JAXBContext.newInstance(BoundClass.class);
        Marshaller marshaller = jxbc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);
        marshaller.marshal(new JAXBElement(new QName("root"),BoundClass.class,new Main("test")),System.out);
    }
}

答案 3 :(得分:1)

标准JAXP API不支持,我为此目的使用了JDom库。它有打印机功能,格式化程序选项等。http://www.jdom.org/

答案 4 :(得分:1)

使用一个班轮试试jcabi-xml

String xml = new XMLDocument(element).toString();

答案 5 :(得分:0)

使用VTD-XML,您可以传入游标并进行单个getElementFragment调用以检索该段(由其偏移量和长度表示)...下面是一个示例

import com.ximpleware.*;
public class concatTest{
    public static void main(String s1[]) throws Exception {
        VTDGen vg= new VTDGen();
        String s = "<users><user><firstName>some </firstName><lastName> one</lastName></user></users>";
        vg.setDoc(s.getBytes());
        vg.parse(false);
        VTDNav vn = vg.getNav();
        AutoPilot ap = new AutoPilot(vn);
        ap.selectXPath("/users/user/firstName");
        int i=ap.evalXPath();
        if (i!=1){
            long l= vn.getElementFragment();
            System.out.println(" the segment is "+ vn.toString((int)l,(int)(l>>32)));
        }
    }

}

答案 6 :(得分:0)

这就是我在jcabi中所做的:

private String asString(Node node) {
    StringWriter writer = new StringWriter();
    try {
        Transformer trans = TransformerFactory.newInstance().newTransformer();
        // @checkstyle MultipleStringLiterals (1 line)
        trans.setOutputProperty(OutputKeys.INDENT, "yes");
        trans.setOutputProperty(OutputKeys.VERSION, "1.0");
        if (!(node instanceof Document)) {
            trans.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
        }
        trans.transform(new DOMSource(node), new StreamResult(writer));
    } catch (final TransformerConfigurationException ex) {
        throw new IllegalStateException(ex);
    } catch (final TransformerException ex) {
        throw new IllegalArgumentException(ex);
    }
    return writer.toString();
}

它对我有用!