线性探测哈希表插入

时间:2012-08-30 02:44:08

标签: c hashtable

== 3139 ==条件跳转或移动取决于未初始化的值

== 3139 ==在0x4A0673F:strcpy(mc_replace_strmem.c:311)

== 3139 == by 0x400ADB:htable_insert(hashtable.c:56)

== 3139 == by 0x400F25:main(mylib.c:11)

大家好,我还在尝试插入哈希表。我不能让它工作,我已经包括我的打印方法,只是因为我认为这可能是一个问题。我正在尝试进行线性探测。当我运行valgrind时,我收到了这个错误,我认为它与复制到我的字符串有关,但我不确定是什么意思?我真的不知道如何让这个插入工作,一些输入将是美妙的..
哈希表插入中的第56行是strcpy(str,key)

int htable_insert(htable h, char *str) {
   int i;
   /*convert string to integer*/
   unsigned int index = htable_word_to_int(str);
   /*calculate index to insert into hash table*/
   int remainder = index%h->capacity;
   /*once calculated position in the hash table, 3 possibilities occur*/
   /*no string in this positon, copy string to that position, increment number of keys, return 1*/
   if (h->key[remainder] == NULL) {
      char *key = emalloc(strlen(str) + 1);
      strcpy(str, key);
      h->key[remainder] = key;
      h->frequencies[remainder] = 1;
      h->num_keys++;
      return 1;
   }
   /*the exact same string is at the position, increment frequency at that position, return frequency*/
   if (strcmp(str, h->key[remainder]) == 0) {
      h->frequencies[remainder]++;
      return h->frequencies[remainder];
   }/*a string is at that position, but it isnt the rightone, keep moving along the array
      until you find either an open space or the string you are looking for*/
   if (h->key[remainder] != NULL && strcmp(str, h->key[remainder]) != 0) {
      /*you may need to wrap back around to the beginning of the table, so each time you add
        to the position you should also mod by the table capacity.*/
      for (i = 0; i <= h->capacity; i++) {
         /*no string in this positon, copy string to that position, increment number of keys*/
         if (h->key[remainder] == NULL) {
            char *key = emalloc(strlen(str) + 1);
            strcpy(str, key);
            h->key[remainder] = key;
            h->frequencies[remainder] = 1;
            h->num_keys++;
         }
         /*if you find the string you were looking for, increment the frequecny at the position
           and return the frequency*/
         if (strcmp(str, h->key[remainder]) == 0) {
            h->frequencies[remainder]++;
            return h->frequencies[remainder];
         }
         if (h->key[remainder] != NULL && h->capacity ==  i) {
            i = 0;
         }
      }   
   }
   /*if you have kept looking for an open space but there isnt one, the hash table must fu*/
   return 0;
}

void htable_print(htable h, FILE *stream) {
   int i;
   for(i = 0; i < h->capacity; i++) {
      if(h->key[i] != NULL) {
         fprintf(stream, "%d%s\n", h->frequencies[i], h->key[i]);
      }
   }
}

1 个答案:

答案 0 :(得分:1)

你的strcpy应该是strcpy(key,str),而不是相反。 (你可以使用strdup,btw,并保存malloc + strcpy)。

另外,在:    if(h-&gt; key [remainder]!= NULL&amp;&amp; strcmp(str,h-&gt; key [remainder])!= 0){

条件“h-&gt; key [余数]!= NULL”是多余的:您已经检查过上述情况。

最后,在你的循环中(越过桶),它似乎是:

  1. 循环条件应为&lt;,not&lt; =
  2. 你应该在某处增加余数,或者使用“余数+ i”和索引到h-&gt;键
  3. 而不是“capacity == i” - &gt; “i = 0”,只需使用“(余数+ i)%容量”作为h-&gt;键的索引
  4. ..最后终于 - 初始部分,即循环之外的部分,可以在循环中,节省代码。