我有一个方法:
private List<String> userCns = Collections.synchronizedList(new ArrayList<String>());
private List<String> recipients = Collections.synchronizedList(new ArrayList<String>());
public void sendEmailToLegalUsers() {
try {
synchronized (lock) {
searchGroup();
if(userCns.size() > 0) {
for(String userCn : userCns) {
String mail = getUserMail(userCn);
if(mail != null) {
recipients.add(mail);
}
}
}
String docName = m_binder.getLocal("docname");
String docId = m_binder.getLocal("docid");
String url = m_binder.getLocal("serverURL");
if(recipients.size() > 0) {
m_binder.addResultSet("LOI_EVIN_MAIL", getLoiEvinMailResultSet(docName, docId, url));
for(String recipient : recipients) {
Log.info("Sending mail to: " + recipient);
InternetFunctions.sendMailToEx(recipient, "MH_LOI_EVIN_SEND_EMAIL", "Update Evin Law Compliance for the item: " + docName, m_service, true);
}
}
}
} catch (Exception e) {
Log.info("Error occurred in LDAPSendMail: "+ e.getMessage());
}
}
现在可以从不同的线程调用此sendEmailToLegalUsers方法。我想知道它是否是锁定代码块的正确方法,以便列表中没有数据混淆的可能性?
编辑:全班:
package com.edifixio.ldapsendmail.handlers;
import intradoc.common.Log;
import intradoc.data.DataResultSet;
import intradoc.server.InternetFunctions;
import intradoc.server.ServiceHandler;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Hashtable;
import java.util.List;
import java.util.Vector;
import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.Attribute;
import javax.naming.directory.Attributes;
import javax.naming.directory.DirContext;
import javax.naming.directory.InitialDirContext;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;
public class LDAPSendMail extends ServiceHandler {
private final Object lock = new Object();
private String ldapURL;
private String baseDN;
private String groupDN;
private String username;
private String password;
private DirContext context;
private List<String> userCns = Collections.synchronizedList(new ArrayList<String>());
private List<String> recipients = Collections.synchronizedList(new ArrayList<String>());
public void sendEmailToLegalUsers() {
try {
synchronized (lock) {
searchGroup();
if(userCns.size() > 0) {
for(String userCn : userCns) {
String mail = getUserMail(userCn);
if(mail != null) {
recipients.add(mail);
}
}
}
String docName = m_binder.getLocal("docname");
String docId = m_binder.getLocal("docid");
String url = m_binder.getLocal("serverURL");
if(recipients.size() > 0) {
m_binder.addResultSet("LOI_EVIN_MAIL", getLoiEvinMailResultSet(docName, docId, url));
for(String recipient : recipients) {
Log.info("Sending mail to: " + recipient);
InternetFunctions.sendMailToEx(recipient, "MH_LOI_EVIN_SEND_EMAIL", "Update Evin Law Compliance for the item: " + docName, m_service, true);
}
}
userCns.clear();
recipients.clear();
}
} catch (Exception e) {
Log.info("Error occurred in LDAPSendMail: "+ e.getMessage());
}
}
private String getUserMail(String userCn) throws NamingException {
NamingEnumeration<SearchResult> searchResults = getLdapDirContext().search(userCn, "(objectclass=person)", getSearchControls());
while (searchResults.hasMore()){
SearchResult searchResult = searchResults.next();
Attributes attributes = searchResult.getAttributes();
Attribute mail = null;
try {
mail = attributes.get("mail");
} catch (Exception e) {
mail = null;
}
if(mail != null) {
return (String)mail.get();
}
}
return null;
}
private void searchGroup() throws NamingException {
NamingEnumeration<SearchResult> searchResults = getLdapDirContext().search(groupDN, "(objectclass=groupOfUniqueNames)", getSearchControls());
String searchGroupCn = getCNForBrand(m_binder.getLocal("brandId"), m_binder.getLocal("brandName"));
while (searchResults.hasMore()) {
SearchResult searchResult = searchResults.next();
Attributes attributes = searchResult.getAttributes();
Attribute groupCn = null;
try {
groupCn = attributes.get("cn");
} catch (Exception e) {
groupCn = null;
}
if(groupCn != null) {
if(searchGroupCn.equals((String)groupCn.get())) {
Attribute uniqueMembers = attributes.get("uniqueMember");
for(int i = 0; i < uniqueMembers.size(); i++){
String uniqueMemberCN = (String) uniqueMembers.get(i);
userCns.add(uniqueMemberCN);
}
break;
}
}
}
}
private DirContext getLdapDirContext() throws NamingException {
if(context != null) {
return context;
}
ldapURL = m_binder.getLocal("ldapUrl");
baseDN = m_binder.getLocal("baseDN");
groupDN = new StringBuilder().append("ou=").append(getAccountGroup(m_binder.getLocal("account"))).append(",").append("ou=groups,").append(baseDN).toString();
username = m_binder.getLocal("username");
password = m_binder.getLocal("password");
Hashtable<String, String> environment = new Hashtable<String, String>();
environment.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
environment.put(Context.PROVIDER_URL, ldapURL);
environment.put(Context.SECURITY_PRINCIPAL, username);
environment.put(Context.SECURITY_CREDENTIALS, password);
context = new InitialDirContext(environment);
return context;
}
private SearchControls getSearchControls() {
SearchControls searchControls = new SearchControls();
searchControls.setSearchScope(SearchControls.SUBTREE_SCOPE);
return searchControls;
}
private String getCNForBrand(String brandId, String brandName) {
String[] brandIdSplittedArray = brandId.split("/");
return new StringBuilder().append(brandIdSplittedArray[0]).append("-").append(brandIdSplittedArray[1]).append("-").
append(brandIdSplittedArray[2]).append("-").append(brandName.replaceAll("\\s","")).append("-LU").toString();
}
private String getAccountGroup(String account) {
return account.split("/")[1];
}
private DataResultSet getLoiEvinMailResultSet(String docName, String docId, String url) {
DataResultSet resultSet = new DataResultSet(new String[]{"DOCNAME", "DOCID", "URL"});
Vector<String> vector = new Vector<String>();
vector.add(docName);
vector.add(docId);
vector.add(url);
resultSet.addRow(vector);
return resultSet;
}
}
答案 0 :(得分:1)
什么是lock
?你在其他地方使用它吗?通常,您希望同步块非常小。如果你在任何地方都使用lock
作为通用锁,那么你可能会阻止一个线程在完全不相关的区域(即没有共享资源争用的区域)中做一些有用的工作。
其次,recipients
真的需要成为实例变量吗?您不断向recipients
添加电子邮件,而不检查列表中是否已存在该电子邮件,这似乎很奇怪。我无法看到您正在清除recipients
的任何代码。这是一个潜在的问题。如果您每次都要从头开始构建recipients
,那么只需在方法中将其设置为局部变量即可。如果您确实需要访问该数据,则可以随时将其从userCns
中删除。
将recipients
作为局部变量后,只需使用userCns
作为锁定进行同步:
synchronized(userCns) {
...
}
编辑:您的代码显示您只使用recipients
一次,而且它位于sendEmailToLegalUsers
方法内。正如我所指出的,另一件事是你永远不会清除recipients
所以这是你代码中的错误。由于您未在任何地方使用recipients
,因此请将其设为sendEmailToLEgalUsers
的局部变量。此外,只需在userCns
上进行同步。您无需同步recipients
;你可以在synchronized块中创建它。
答案 1 :(得分:1)
我愿意
private final List<String> userCns = new ArrayList<String>();
private final List<String> recipients = new ArrayList<String>();
与
synchronized(userCns) {
// as Vivin suggests.
}
您不需要额外的锁定。